Question

运行php代码时出现以下错误。我正在尝试创建注册表单，但它始终显示以下错误消息。

解析错误：语法错误，意外的'$ username'（T_VARIABLE），期待第15行/home/xxx/public_html/dashboard.php中的']'

请帮我解决这个问题

<?php
  session_start();
  require 'config.php'; 
  if (isset($_POST['register_btn])){
     session_start();
     $username = mysql_real_escape_string($_POST["username"]);
     $firstName = mysql_real_escape_string($_POST["firstName"]);
     $lastName = mysql_real_escape_string($_POST["lastName"]);
     $email = mysql_real_escape_string($_POST["email"]);
     $password = mysql_real_escape_string($_POST["password"]);
     $password2 = mysql_real_escape_string($_POST["password2"]);
     if ($password == $password2){
        $password = md5($password);
       $sql = "INSERT INTO users(username, firstName, lastName, email, password, password2) 
       VALUES('$username', '$firstName', '$lastName', '$email', '$password', '$password2')"; 
       mysqli_query($conn, $sql);
       $_SESSION['message'] = "You are successfully logged in";
       $_SESSION['firstName'] = $firstName;
       $_SESSION['lastName'] = $lastName;
   }else {
        $_SESSION['message'] = "The Two password do not match";
       }

    }


?>

Answer 1

您忘记关闭'中的单引号if (isset($_POST['register_btn'])){。

运行以下代码。

<?php
  session_start();
  require 'config.php'; 
  if (isset($_POST['register_btn'])){
     session_start();
     $username = mysql_real_escape_string($_POST["username"]);
     $firstName = mysql_real_escape_string($_POST["firstName"]);
     $lastName = mysql_real_escape_string($_POST["lastName"]);
     $email = mysql_real_escape_string($_POST["email"]);
     $password = mysql_real_escape_string($_POST["password"]);
     $password2 = mysql_real_escape_string($_POST["password2"]);

    if ($password == $password2){

       $password = md5($password);
       $sql = "INSERT INTO users(username, firstName, lastName, email, password, password2) 
       VALUES('$username', '$firstName', '$lastName', '$email', '$password', '$password2')"; 
       mysqli_query($conn, $sql);
       $_SESSION['message'] = "You are successfully logged in";
       $_SESSION['firstName'] = $firstName;
       $_SESSION['lastName'] = $lastName;

    }else {
        $_SESSION['message'] = "The Two password do not match";
    }

  }

?>

解析错误：语法错误，意外的'$ username'（T_VARIABLE），在第15行的/home/xxx/public_html/dashboard.php中期待']'

1 个答案: