Question

我有一个下载文件按钮，一旦点击将从网站下载文件并将其保存到通过FileChooser选择的位置和名称，但我很难将文件位置和名称传递给FileOutputStream。

有人有什么建议吗？

谢谢，

保

这是我的代码：

public void GetFile()
{
    try
    {
        URL url = new URL("https://www.myURL.com/MyFile.xlsx");
        FileChooser saveAs = new FileChooser();
        saveAs.setInitialFileName("MyFile.xlsx");
        saveAs.getExtensionFilters().addAll(new FileChooser.ExtensionFilter("Excel Files", "*.xlsx"));
        saveAs.showSaveDialog(null);
        System.out.println("File name and location set");
        saveFile(url,saveAs.getInitialDirectory());
    }
    catch(IOException e)
    {
        e.printStackTrace();
    }
}


public void saveFile(URL url, File saveAs) throws IOException {
    System.out.println("opening connection");
    InputStream in = url.openStream();
    FileOutputStream fos = new FileOutputStream(saveAs);
    System.out.println("Reading file...");
    int length = -1;
    byte[] buffer = new byte[1024];
    while ((length = in.read(buffer)) > -1) {
        fos.write(buffer, 0, length);
    }

    fos.close();
    in.close();
    System.out.println("File downloaded");
}

Answer 1

使用FileChooser.showSaveDialog的返回值代替initialDirectory属性值：

File outputFile = saveAs.showSaveDialog(null);

if (outputFile != null) {
    System.out.println("File name and location set");
    saveFile(url, outputFile);
}

JavaFX FileChooser目录和文件名传递给FileOutputStream

1 个答案: