Question

我正在尝试创建历史。我有两个活动。一个是用户在editText中输入值并将其存储在共享首选项中，另一个用于使用共享首选项以列表视图形式显示值。我不知道错误是什么，因为应用程序崩溃了。

第一项活动

 package com.example.sy.list;

 import android.content.Context;
 import android.content.Intent;
 import android.content.SharedPreferences;
 import android.support.v7.app.AppCompatActivity;
 import android.os.Bundle;
 import android.view.View;
 import android.view.inputmethod.InputMethodManager;
 import android.widget.Button;
 import android.widget.EditText;


 public class History extends AppCompatActivity {
Button translate;
Button next;
EditText enterText;
private SharedPreferences hPreferences;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.history);

    enterText = findViewById(R.id.editText);
    next = findViewById(R.id.btnNext);

    translate = findViewById(R.id.buttonTranslate);
    View.OnClickListener addlistener = new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
            imm.hideSoftInputFromWindow(enterText.getWindowToken(), 0);
            hPreferences  = getSharedPreferences("SaveHistory",Context.MODE_PRIVATE);
            SharedPreferences.Editor editor = hPreferences.edit();
            editor.putString("history",enterText.getText().toString());
            editor.apply();
            enterText.setText("");



        }

    };
    translate.setOnClickListener(addlistener);
    next.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            Intent intent = new Intent(History.this,MainActivity.class);
            startActivity(intent);
        }
    });



}

}

第二项活动

 package com.example.sy.list;

 import android.content.Context;
 import android.content.SharedPreferences;
 import android.support.v7.app.AppCompatActivity;
 import android.os.Bundle;
 import android.view.ActionMode;
 import android.view.Menu;
 import android.view.MenuInflater;
 import android.view.MenuItem;
 import android.widget.AbsListView;
 import android.widget.ArrayAdapter;
 import android.widget.ListView;
 import java.util.ArrayList;


public class MainActivity extends AppCompatActivity {
private ListView listView;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    ArrayList<String> itemList = new ArrayList<String>();
    ArrayAdapter<String> adapter;
    adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, itemList);
    listView.setAdapter(adapter);

    listView = findViewById(R.id.listView);
    SharedPreferences transHistory  = getSharedPreferences("SaveHistory",Context.MODE_PRIVATE);
    String tHistory = transHistory.getString("history","Data Not Found");
    itemList.add(tHistory);
    adapter.notifyDataSetChanged();


}

}

Answer 1

你错误的原因可能是：

listView.setAdapter（适配器）;

listView = findViewById（R.id.listView）;

首先，您设置了适配器listView.setAdapter(adapter);但问题是，因为您调用了listView

，listView = findViewByIt(R.id.listview);不为空

所以，切换语句，你应该好好去

修改

listView = findViewById(R.id.listView);

然后

listView.setAdapter(adapter);

使用共享首选项以列表视图形式显示输入值

1 个答案: