Question

编写几种数组操作方法。一种方法将总结一部分提供数组，另一种方法将计算数组中出现的特定数量的多少，以及最后一个方法将从数组中删除所有特定值。

我已经完成了代码，但是我退出了反弹：9错误，我无法解决它。

import java.lang.System;
import java.lang.Math;

public class ArrayFunHouse {
    // instance variables and constructors could be used, but are not really
    // needed

    // getSum() will return the sum of the numbers from start to stop, not
    // including stop
    public static int getSum(int[] numArray, int start, int stop)
    {
        int sum = 0;
        int[] locArray = numArray;

        for(int i = start; i<=stop; i++)
        {
            sum+=locArray[i];
        }

        return sum;
    }

    // getCount() will return number of times val is present
    public static int getCount(int[] numArray, int val) 
    {
        int times = 0;
        for (int i : numArray) 
        {
            if (i == val)
                times++;
        }
        return times;
    }

    public static int[] removeVal(int[] numArray, int val) 
    {
        int[] array = new int[numArray.length - getCount(numArray, val)];
        byte index = 0;
        for (int i : numArray) 
        {
            if (i != val) {
                array[index] = i;
                index++;enter code here
            }
        }
        return array;
    }

}

我的跑步者班级

import java.util.Arrays;

public class ArrayFunHouseRunner
{
    public static void main( String args[] )
    {
        int[] one = {7, 4, 10, 0, 1, 7, 6, 5, 3, 2, 9, 7};

        System.out.println(Arrays.toString(one));
        System.out.println("sum of spots 3-6  =  " + 
        ArrayFunHouse.getSum(one,3,6));
        System.out.println("sum of spots 2-9  =  " + 
        ArrayFunHouse.getSum(one,2,9));
        System.out.println("# of 4s  =  " + ArrayFunHouse.getCount(one,4));
        System.out.println("# of 9s  =  " + ArrayFunHouse.getCount(one,9));
        System.out.println("# of 7s  =  " + ArrayFunHouse.getCount(one,7)); 
        one = ArrayFunHouse.removeVal(one, 7);
        System.out.println("new array with all 7s removed  =  " + 
        Arrays.toString(one));
        System.out.println("# of 7s  =  " + ArrayFunHouse.getCount(one, 7));

       System.out.println();

       int[] two = {7, 4, 2, 7, 3, 4, 6, 7, 8, 9, 7, 0, 10, 7, 0, 1, 7, 6, 5, 7, 3, 2, 7, 9, 9, 8,7};        

       System.out.println(Arrays.toString(one));
       System.out.println("sum of spots 3-16  =  " + 
       ArrayFunHouse.getSum(one,3,16));
       System.out.println("sum of spots 2-9  =  " + 
       ArrayFunHouse.getSum(one,2,9));
       System.out.println("# of 4s  =  " + ArrayFunHouse.getCount(one,4));
       System.out.println("# of 9s  =  " + ArrayFunHouse.getCount(one,9));
       System.out.println("# of 7s  =  " + ArrayFunHouse.getCount(one,7)); 
       one = ArrayFunHouse.removeVal(one, 7);
       System.out.println("new array with all 7s removed  =  " + 
       Arrays.toString(one));
       System.out.println("# of 7s  =  " + ArrayFunHouse.getCount(one, 7));
    }
}

我的输出

 [7, 4, 10, 0, 1, 7, 6, 5, 3, 2, 9, 7]
sum of spots 3-6  =  14
sum of spots 2-9  =  34
 # of 4s  =  1
# of 9s  =  1
# of 7s  =  3
new array with all 7s removed  =  [4, 10, 0, 1, 6, 5, 3, 2, 9]
# of 7s  =  0

[4, 10, 0, 1, 6, 5, 3, 2, 9]
 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 9
 at ArrayFunHouse.getSum(ArrayFunHouse.java:22)
 at ArrayFunHouseRunner.main(ArrayFunHouseRunner.java:30)

我需要帮助。第一个工作正常，但第二个出错。

Answer 1

在这行代码：ArrayFunHouse.getSum(one,3,16));中，您将停止索引16传递给第一个数组，您需要做的是将其传递给第二个数组 2 即可。这是因为第一个数组的长度小于16.另外，在其他一些代码行中，你传入了一个，而不是传入两个。试试它是否有效。

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