Question

我的代码正在尝试：

创建User模型
使用与新创建的用户相同的电子邮件地址在Subscriber模型中查找实例
将新用户的subscribedAccount媒体资源与Subscriber

findOne

user.email

代码：

// Check that I have a subscriber with email 'test@test.com'
Subscriber.findOne({email:'test@test.com'})
          .then(d => console.log(`\nResult of check for a subscriber with email test@test.com:\n ${d}`));

User.create({name: {first: 'test first', last: 'test last'}, email: 'test@test.com', password: 'pass123'})
.then(u => {
  user = u;
  // Check that user.email contains 'test@test.com'
  console.log(`\nCreated user's email address: ${user.email}\n`);
  Subscriber.findOne({email: user.email});
})
.then(s => {
  console.log(`\nAnything found by findOne and passed to this .then()?: ${s}`);
  user.subscribedAccount = s;
  user.save();
})
.catch(e => console.log(e.message));

控制台结果：

在http://localhost:3000运行的服务器已成功连接   猫鼬！

通过电子邮件test@test.com检查订户的结果：
  {组：   []，_ id：5aa422736518f30fbc0f77e2，姓名：＆＃39;测试名称＆＃39;，电子邮件：   ＆＃39; test@test.com' ;,zipCode：11111，__ v：0}

创建用户的电子邮件地址：test@test.com

findOne发现并传递给此.then（）？：undefined

为什么Subscriber.findOne会返回undefined？这是实际发生的事情还是我失踪的其他事情？

以下是User和Subscriber的模型定义。如果您需要从应用程序中查看其他内容以告知发生了什么，请告诉我。

User：

const mongoose = require('mongoose');
const {Schema} = require('mongoose');

var userSchema = new Schema( {
  name: {
    first: {
      type: String,
      trim: true
    },
    last: {
      type: String,
      trim: true
    }
  },
  email: {
    type: String,
    required: true,
    lowercase: true,
    unique: true
  },
  zipCode: {
    type: Number,
    min: [ 10000, 'Zip code too short' ],
    max: 99999
  },
  password: {
    type: String,
    required: true
  },
  courses: [ {
    type: Schema.Types.ObjectId,
    ref: 'Course'
  } ],
  subscribedAccount: {
    type: Schema.Types.ObjectId,
    ref: 'Subscriber'
  }
}, {
  timestamps: true
} );

userSchema.virtual('fullName').get(function() {
  return `${this.name.first} ${this.name.last}`;

});
module.exports = mongoose.model('User', userSchema);

Subscriber：

const mongoose = require('mongoose');
const Schema = mongoose.Schema;

let subscriberSchema = new Schema({
  name: {
    type: String,
    required: true
  },
  email: {
    type: String,
    required: true,
    lowercase: true,
    unique: true
  },
  zipCode: {
    type: Number,
    min: [10000, 'Zip Code too short'],
    max: 99999
  },
  groups: [{type: Schema.Types.ObjectId, ref: 'Group'}]
});

subscriberSchema.methods.getInfo = function() {
  return `Name: ${this.name} Email: ${this.email} Zip Code: ${this.zipCode}`;
}
subscriberSchema.methods.findLocalSubscribers = function() {
  return this.model('Subscriber')
             .find({zipCode: this.zipCode})
             .exec();
}

//model.exports = mongoose.model('Subcriber', subscriberSchema);

var Subscriber = exports.Subscriber = mongoose.model('Subscriber', subscriberSchema);

Answer 1

你应该这样做

// Check that I have a subscriber with email 'test@test.com'
    Subscriber.findOne({email:'test@test.com'})
              .then(d => console.log(`\nResult of check for a subscriber with email test@test.com:\n ${d}`));

    User.create({name: {first: 'test first', last: 'test last'}, email: 'test@test.com', password: 'pass123'})
    .then(u => {
      user = u;
      // Check that user.email contains 'test@test.com'
      console.log(`\nCreated user's email address: ${user.email}\n`);
      Subscriber.findOne({email: user.email});


      console.log(`\nAnything found by findOne and passed to this .then()?: ${s}`);
      user.subscribedAccount = s;
      user.save()
      .then(s => {
            //user has been updated
        })
      .catch(err => {
         res.status(err).json(err);
         })

      })
       })
     . catch(e => console.log(e.message));

nodejs / mongoose：我的链接.then（）调用有什么问题

1 个答案: