Question

我有一堆像这样的字符串：

t='Enter  FLAVIUS ,                         MURELLUS , a  CARPENTER , a
                         COBBLER , and certain other
                     COMMONERS  over the stage    !  '

即。多个空格的字符串。如果应用以下正则表达式，我设法将多个空格转换为仅一个空格，这就是我想要的：

re.sub(' +',' ',t)
OUTPUT: 'Enter FLAVIUS , MURELLUS , a CARPENTER , a COBBLER , and certain other COMMONERS over the stage !'

我现在需要摆脱一个标点符号之间不必要的空格。

换句话说，我希望输出为：

OUTPUT: 'Enter FLAVIUS, MURELLUS, a CARPENTER, a COBBLER, and certain other COMMONERS over the stage!'

我该怎么做？

Answer 1

import re
t='Enter  FLAVIUS ,                         MURELLUS , a  CARPENTER , a                         COBBLER , and certain other                     COMMONERS  over the stage    !  '
print(re.sub('\s+(?=[!,])','',re.sub(' +',' ',t)))

输出

Enter FLAVIUS, MURELLUS, a CARPENTER, a COBBLER, and certain other COMMONERS over the stage!

在正则表达式后删除不必要的空格

1 个答案: