Question

我想查看一些我通过html和php代码添加到数据库中的食物像食物a，食物b，食物c，食物d。

我希望在html的另一页下拉列表中查看这些食物类别作为更新食品类别。

＆＃13;

<?php
$db_host = 'localhost'; // Server Name
$db_user = 'root'; // Username
$db_pass = ''; // Password
$db_name = 'rfid'; // Database Name

$conn = mysqli_connect($db_host, $db_user, $db_pass, $db_name);
if (!$conn) {
	die ('Failed to connect to MySQL: ' . mysqli_connect_error());	
}

?>  
	 <div class="sign_up">
		
				<div class="formtitle" align="center">View Food Items </div>
				<div class="top_section">
					<div class="section">
					<br>
				  <div class="input-sign details2">
				  <form name="form1" action="" method="post">
					  &nbsp;&nbsp; View Foods: 
					    <?php
					   if ($result = @$dbconn->query("SELECT * FROM `food`")) 
					   {
					   //`food` represents the table name.
          echo "<select>";
          while ($row = $result->fetch_assoc()) 
		  {
            echo "<option value=\"".$row["food"]."\">".$row["food"]."</option>";
            /*"id" and "foodname" represents the table column name.*/
          }
          echo "</select>";
        }
					  ?>
							<select>
								<option><?php echo $row["food"];?></option>
					  </select>
					  
					  </form>
						</div>      
					</div>    
					</div>
	<div class="clear"> </div>
	 </div>

＆＃13;

Answer 1

这可能与您的报价有关，请尝试echo "<option value=\"".$row['food']."\">".$row["food"]."</option>"; 此外，我发现this类似问题可以帮助您解决问题。致作者@SpaceBeers

Answer 2

所以我假设您知道如何连接数据库并使用它。

以下是您想要的示例。

        if ($result = $dbconn->query("SELECT * FROM `food`")) {
          //`food` represents the table name.
          echo "<select>";
          while ($row = $result->fetch_assoc()) {
            echo "<option value=\"".row["id"]."\">".row["foodname"]."</option>";
            /*"id" and "foodname" represents the table column name.*/
          }
          echo "</select>";
        }

查看我的更新数据从mysql到下拉列表

2 个答案: