在DB :: raw和2个表中选择COUNT

Question

我有两张桌子：

类别：

idCat, nameCat, urlCat

详细信息：

idDetailPost, nameDetailPost, viewDetailPost, idCat

这意味着1个类别有很多帖子。我的问题是：我需要网站上的表格：

nameCat 
urlCat 
count(post in category)
count(viewDetailPost)

这是SQL权利。我在XAMPP中测试了它：

SELECT
     c.nameCat AS nameCategory,
     c.urlCat AS urlCategory,
     COUNT(d.idCat) AS countPost,
     COUNT(d.viewDetailPost) AS viewPost FROM
     category c,
     detailpost d WHERE
     c.idCat = d.idCat GROUP BY
     d.idCat

但我不知道如何在Laravel 5.4中编写它。我试过DB :: raw，DB :: select，join ...请帮忙！谢谢！

Answer 1

DB::table('detailpost as dp')
->leftJoin('category as c','c.id','=','dp.idCat')
->select( 'c.nameCat AS nameCategory', 'c.urlCat AS urlCategory',DB::raw('count(dp.idCat) as countPost),DB::raw('count(dp.viewDetailPost) as viewPost ))
->groupBy('dp.idCat')
->get();

Answer 2

非常感谢！这是答案！

$sql =  DB::table('detailpost')
            ->select(
                'category.nameCat AS name_category',
                'category.urlCat AS url_category' ,
                DB::raw('count(detailpost.idCat) as count_post'),
                DB::raw('count(detailpost.viewDetailPost) as view_post')
            )
            ->leftJoin('category','detailpost.idCat','category.idCat')
            ->groupBy('category.nameCat', 'category.urlCat')
            ->orderBy('detailpost.idCat', 'ASC')
            ->get();

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