这是我的代码
structure1
export class BankingChannePageData<T> {
pagedata: T;
revnum: number;
pagetype: string;
}
structur2
import { BankingChannelCommonRevenueCenter } from '../../models/banking-channel/banking-channel-common-revenue-center';
export class BankingChannelRevenueCenter<T> {
common: BankingChannelCommonRevenueCenter;
specific: T;
}
Strurture 3
export class BankingChannelCommonRevenueCenter {
stateid: number;
statename: string;
districtid: number;
districtname: string;
subdistrictid: number;
subdistrictname: string;
centerid: number;
centername: string;
bankid: number;
}
这里我创建了一个数组
bcrevenuecenterarray: BankingChannelCommonRevenueCenter[] = [];
并将创建的数组分配给通用对象 像这样
const bcrevenuecenterrequest = new BankingChannePageData<BankingChannelRevenueCenter<any>>();
bcrevenuecenterrequest.pagedata = new BankingChannelRevenueCenter<any>();
bcrevenuecenterrequest.pagedata.common = new BankingChannelCommonRevenueCenter();
bcrevenuecenterrequest.pagedata.common = this.bcrevenuecenterarray;
问题 键入&#39; BankingChannelCommonRevenueCenter []&#39;不能分配给类型&#39; BankingChannelCommonRevenueCenter&#39;。 财产&#39; stateid&#39;在&#39; BankingChannelCommonRevenueCenter []&#39;。
中缺少答案 0 :(得分:1)
您已将该字段声明为BankingChannelCommonRevenueCenter对象的数组,但之后您尝试将该值设置为单个BankingChannelCommonRevenueCenter。
BankingChannelCommonRevenueCenter []表示“数组中每个项目都是BankingChannelCommonRevenueCenter实例的数组”。
如果您希望该字段仅包含一个项目,则将其类型声明为 BankingChannelCommonRevenueCenter代替BankingChannelCommonRevenueCenter [](删除方括号)。