我需要从给定字符串中提取用大括号标记的标记。
我尝试使用Expresso来构造可以解析的东西......
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"{Token1}asdasasd{Token2}asd asdacscadase dfb db {Token3}"
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并生成“Token1”,“Token2”,“Token3”
我尝试过使用..
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({.+})
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......但这似乎与整个表达相匹配。
有什么想法吗?
答案 0 :(得分:6)
尝试
\{(.*?)\}
The \{ will escape the "{" (which has meaning in a RegEx). The \} likewise escapes the closing } backet. The .*? will take minimal data, instead of just .* which is "greedy" and takes everything it can.
If you have assurance that your tokens will (or need to) be of a specific format, you can replace .* with an appropriate character class. For example, in the likely case you want only words, you can use (\w*) in place of the (.*?) This has the advantage that closing } characters are not part of the class being matched in the inner expression, so you don't need the ? modifier).
答案 1 :(得分:2)
尝试:
\{([^}]*)\}
这会将搜索范围内的搜索限制在关闭支撑上停止。
答案 2 :(得分:2)
另一种解决方案:
(?<=\{)([^\}]+)(?=\})
这使用前瞻和后视,因此根本不会消耗括号。
答案 3 :(得分:1)
大括号在正则表达式中具有特殊含义,因此您必须将它们转义。使用\{
和\}
匹配它们。