Question

我有两张表文件和 poi_data 。文档包含两种类型的表单 ETP 和 FP10 。我想基于数字和下面查询中显示的两个别名的总和来计算两种形式。不幸的是它不起作用。

Document Table (id,title ,type ,status)
poi_data Table (poi_id, doc_id, form_number, status)

SELECT 
COUNT(DISTINCT CASE WHEN documents.title LIKE '%ETP%' THEN poi_data.form_number END) AS form_count_one,
COUNT(DISTINCT CASE WHEN documents.title LIKE '%FP10%' THEN poi_data.form_number END) AS form_count_two, 
SUM(form_count_one + form_count_two) as total_form_count FROM poi_data 
LEFT JOIN documents ON (poi_data.doc_id = documents.id AND documents.status = 1) 
WHERE poi_data.pid = 781 AND poi_data.poi_id = 8

Answer 1

只需使用子查询：

SELECT form_count_one, form_count_two
       (form_count_one + form_count_two) as total_form_count 
FROM (SELECT COUNT(DISTINCT CASE WHEN d.title LIKE '%ETP%' THEN pd.form_number END) AS form_count_one,
             COUNT(DISTINCT CASE WHEN d.title LIKE '%FP10%' THEN pd.form_number END) AS form_count_two 
      FROM poi_data pd LEFT JOIN
           documents d
           ON pd.doc_id = d.id AND d.status = 1
      WHERE pd.pid = 781 AND pd.poi_id = 8
     ) d

Answer 2

选择

（COUNT（当文件。标题类似'％ETP％'，然后poi_data.form_number结束时的DISTINCT案例）+ COUNT（当document.title LIKE'％FP10％'那么poi_data.form_number结束时的DISTINCT案例）AS total_form_count FROM poi_data LEFT JOIN文件ON（poi_data.doc_id = documents.id AND documents.status = 1）在哪里poi_data.pid = 781 AND poi_data.poi_id = 8

你不需要使用SUM，因为你只想要数不是平均数或什么。然后使用“+”

简单地添加它们

Answer 3

应该是

select SUM(form_count_one + form_count_two) as total_form_count from (SELECT 
COUNT(DISTINCT CASE WHEN documents.title LIKE '%ETP%' THEN poi_data.form_number END) AS form_count_one,
COUNT(DISTINCT CASE WHEN documents.title LIKE '%FP10%' THEN poi_data.form_number END) AS form_count_two, 
 FROM poi_data 
LEFT JOIN documents ON (poi_data.doc_id = documents.id AND documents.status = 1) 
WHERE poi_data.pid = 781 AND poi_data.poi_id = 8)alias_name

mysql两个alias_column的总和不起作用

3 个答案: