Question

我想将PHP变量值和JavaScript变量相乘并在屏幕上显示它。

这是我的代码（PHP文件）：

<?php
require 'config.php';
session_start();
?>
<html>
    <head>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <script src="knockout.js"></script>
        <script src="hello.js" defer="defer"></script>
    </head>
    <body>
        
        <?php
        $uname = $_SESSION['username'];
        $query = "select * abc where username='$uname'";
        $query_run = mysqli_query($con, $query);
        if (mysqli_num_rows($query_run) == 1) {

            while ($rows = mysqli_fetch_array($query_run)) {

                $var1 = $rows['row1'];
                $var1= (int) $var1;
                $_SESSION['var1'] = $var1;
            }
        } else {
            echo $uname;
        }
        ?>

    </body>
</html>

这是我的JavaScript代码：

$.ajax({
    type: "GET",

    url: "url"
}).done(function (data) {
    var abc = JSON.parse(data);
    var a=abc['rows'];

});

我希望将PHP变量$var1和JavaScript变量a相乘，并将其显示在屏幕上。

Answer 1

您必须将php变量传递给外部脚本文件在php文件中：

<script>var var1 = "<?php echo $var1; $?>"</script>

然后在脚本文件中，您可以使用此var1变量

并且您的脚本文件必须在php脚本意味着在页脚

之后加载

Answer 2

以下是您想要的确切代码。乐于帮助：）

<?php
require 'config.php';
session_start();
?>
<html>
    <head>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <script src="knockout.js"></script>
        <script src="hello.js" defer="defer"></script>
    </head>
    <body>
        
        <?php
        $uname = $_SESSION['username'];
        $query = "select * abc where username='$uname'";
        $query_run = mysqli_query($con, $query);
        if (mysqli_num_rows($query_run) == 1) {

            while ($rows = mysqli_fetch_array($query_run)) {

                $var1 = $rows['row1'];
                $var1= (int) $var1;
                $_SESSION['var1'] = $var1;
            }
        } else {
            echo $uname;
        }
        ?>
        
        <script>var var1 = <?php echo $var1; $?></script>
        <script>
        
          $.ajax({
              type: "GET",
              url: "url"
          }).done(function (data) {
              var abc = JSON.parse(data);
              var a=abc['rows'];
              var result = var1 * a;//now display result variable in the page wherever you want
              document.getElementById("id_of_element_where_you_want_display_result").innerHTML= result;

          });
          
           
        </script>
    </body>
</html>

将JavaScript变量和PHP变量相乘并显示在屏幕上

2 个答案: