Question

我正在尝试将一系列时间与当前本地时间进行比较。但是比较这些数字对某些值来说是失败的据我所知，它并不总是失败同一时间字符串。我真的没有想法是什么原因。

function lastPassedTimeIndex() {
  const d = new Date();
  const nowHr = d.getHours();
  const nowMin = d.getMinutes();

  let lastPassedTimeIndex = 0;
  const currentTimes = ['05:20', '06:57', '12:46', '15:48', '18:30', '20:02'];

  for (const time of currentTimes) {
     const t = time.split(':');
     const printHr = parseInt(t[0], 10);
     const printMin = parseInt(t[1], 10);

     if ((printHr < nowHr) && (printMin < nowMin)) {
        console.log(time, 'previous from now');
        lastPassedTimeIndex++;
     }
     else if ((printHr === nowHr) && (printMin < nowMin)) {
        console.log(time, 'previous from now, but hour is correct');
        lastPassedTimeIndex++;
     }
     else if ((printHr === nowHr) && (printMin >= nowMin)) {
        console.log(time, 'is upcoming or now and hour is correct');
        lastPassedTimeIndex++;
     }
     else if ((printHr > nowHr)) {
        console.log(time, 'is upcoming, hour is larger');
     }
     else {
        console.log('I have no idea!');
     }
  }

  console.log('LastPassedTimeIndex ', lastPassedTimeIndex);
  return lastPassedTimeIndex;
}

这是我的控制台输出：

> I have no idea! 
> I have no idea!
> 12:46 is upcoming, hour is larger
> 15:48 is upcoming, hour is larger
> 18:30 is upcoming, hour is larger
> 20:02 is upcoming, hour is larger
> LastPassedTimeIndex  0

Answer 1

我只看到一个错误，以这种方式修复：

 const printHr = parseInt(t[0], 10);
 const printMin = parseInt(t[1], 10);

 if ((printHr < nowHr) /* Take out what was here */) {
    console.log(time, 'previous from now');
    lastPassedTimeIndex++;
 }

Answer 2

只有当小时数相同时才需要比较分钟，或者只是比较字符串：

var time = new Date().toTimeString().slice(0, 5)
var times = ['05:20', '06:57', '12:46', '15:48', '18:30', '20:02']

console.log( time, times.findIndex(t => t >= time) - 1 )

与解析数字的比较失败

2 个答案: