AWK？在包含符号的每一行附加一个增量编号

Question

我有一个序列文件。

>seqA
lakjdsflakjsdlkjals;dkjfal;kdjsfl;aksdjf;lakjsdfl;kjalsdkjf
alsdkjfalskdjf;alsdfj;alkdjsf;lakjsdf;lkajsd
>seqB
fjal;kdjsfla;kdjsflkajdslkjfaghal;sdkjg
>seqC
a;lksdjl;akjsdg;lkjsdfl;kajdsl;kgj;alkdjsg;lkajsdgl
lsdkfja;lksdjf;lakdjsf;lkajsdfl;kjal;sdkfjal;skdjak
sdkjfal;ksdjflk;ahdglkahsdl;kghalk

我想在每个＆＃34;＆gt;＆＃34;之后添加一个递增的增量数字。

例如：

输出文件：

>1seqA
lakjdsflakjsdlkjals;dkjfal;kdjsfl;aksdjf;lakjsdfl;kjalsdkjf
alsdkjfalskdjf;alsdfj;alkdjsf;lakjsdf;lkajsd
>2seqB
fjal;kdjsfla;kdjsflkajdslkjfaghal;sdkjg
>3seqC
a;lksdjl;akjsdg;lkjsdfl;kajdsl;kgj;alkdjsg;lkajsdgl
lsdkfja;lksdjf;lakdjsf;lkajsdfl;kjal;sdkfjal;skdjak
sdkjfal;ksdjflk;ahdglkahsdl;kghalk

在搜索完互联网后到目前为止，我已尝试过：

awk -F "i=1" '{if (/>/){print $0i++} else print}'

它并没有做任何事情。我做错了什么？

谢谢！

Answer 1

Try:

awk '/>/{$0 = ">" ++i substr($0, 2)} 1'

For example:

$ awk '/>/{$0 = ">" ++i substr($0, 2)} 1' file
>1seqA
lakjdsflakjsdlkjals;dkjfal;kdjsfl;aksdjf;lakjsdfl;kjalsdkjf
alsdkjfalskdjf;alsdfj;alkdjsf;lakjsdf;lkajsd
>2seqB
fjal;kdjsfla;kdjsflkajdslkjfaghal;sdkjg
>3seqC
a;lksdjl;akjsdg;lkjsdfl;kajdsl;kgj;alkdjsg;lkajsdgl
lsdkfja;lksdjf;lakdjsf;lkajsdfl;kjal;sdkfjal;skdjak
sdkjfal;ksdjflk;ahdglkahsdl;kghalk

How it works

• />/{$0 = ">" ++i substr($0, 2)}

  This selects lines that contain >. For those lines, we replace the line $0 with > followed by ++i (which is the value of the variable i after it has been incremented) followed by the current line starting at its second character.

• 1

  This is awk's shorthand for print-the-line.

Answer 2

你可以尝试

awk '/^>/{sub(/^>/,">"++i)}1' infile

Answer 3

略有不同：

awk -F'>' -v OFS='>' 'NF == 2 {$2 = ++count $2} 1' file

那使用＆＃34;＆gt;＆＃34;作为字段分隔符，并使用字段数作为条件。