Question

我正在尝试在调用我的函数时从UIAlertController内调用UITtableViewCell。它给我一个错误，说现在不可用。我知道它不在ViewController范围内。我正在寻找一种方法来访问它。

override func awakeFromNib() {
    super.awakeFromNib()
    // Initialization code

    let tapGestureShareImageView = UITapGestureRecognizer(target: self, action: #selector(self.shareImageTouchUpInside))
    shareImageView.addGestureRecognizer(tapGestureShareImageView)
    shareImageView.isUserInteractionEnabled = true
}

@objc func shareImageTouchUpInside() {
    showAction()
}

func showAction() {
    let alertController = UIAlertController(title: "Action Sheet", message: "What do you like to do", preferredStyle: .alert)

    let okButton = UIAlertAction(title: "Done", style: .default, handler: { (action) -> Void in
        print("Ok button tapped")
    })

    let deleteButton = UIAlertAction(title: "Skip", style: .destructive, handler: { (action) -> Void in
        print("Delete button tapped")
    })

    alertController.addAction(okButton)
    alertController.addAction(deleteButton)

    present(alertController, animated: true, completion: nil)
}

Answer 1

您可以尝试使用委托

protocol AlertShower{
    func showAlert(TableCustomCell)
}

class TableCustomCell: UITableViewCell {
    var delegate: AlertShower?

    @IBAction func showClicked(_ sender: UIButton) {
        self.delegate?.alertShower(sender:self)
    }
}

VC中的

class viewController: UIViewController, AlertShower {

    override func viewDidLoad() {
        super.viewDidLoad()

    }


    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

         let cell = areaSettTable.dequeueReusableCell(withIdentifier:CellIdentifier1) as! TableCustomCell

         cell.delegate = self

         return cell
    }

    func showAlert(sender:TableCustomCell) {

      // show alert here

    }
}

Answer 2

Present仅适用于ViewControllers。您将不得不将触摸事件重定向到视图控制器。最常见的方法是在UITableViewCell中使用委托属性。

https://developer.apple.com/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/Protocols.html#//apple_ref/doc/uid/TP40014097-CH25-ID276

Answer 3

它不适合我。这是我的代码：

import UIKit
protocol AlertShower{
    func showAlert(_: allListsCell)
}

// prototype table cell...
class allListsCell: UITableViewCell {
    var delegate: AlertShower?
    @IBOutlet var cellSelected:    UILabel!
    var colorIndex = Int()        // point directly back to colors[]

    @IBAction func colorEditButton(_ sender: UIButton, forEvent event: UIEvent) {
        self.delegate?.alertShower(sender:self)  // ERROR...
    }
}

上述错误来自编译器：
＆＃34;类型的值＆＃39; AlertShower＆＃39;没有会员＆＃39; alertShower＆＃39;＆＃34;

其余代码：

class tableViews: UITableViewController, AlertShower {
    func showAlert(_: allListsCell) {
    }

    func showAlert(sender:allListsCell) {

        // show alert here

    }
...
}

...帮助？

Answer 4

我在从子类UIView创建自定义活动指标时遇到了类似的问题。我所做的是创建'show'函数（在子类中）并传入UIViewController参数，如下所示：

public func play(inView view: UIViewController) {
//Perform action here
view.present(alertController, animated: true, completion: nil)
}

只需在视图控制器中调用它，就像这样：

CustomClass.play(inView: self)

希望这有帮助！

在UITableViewCell中调用UIAlertController

4 个答案: