我编写了一个程序来根据用户名从Active Directory中获取所有属性。现在我想根据memerOf属性中的组名CN = App_abc_Admin获取电子邮件地址列表。
Main .java
public void ldapQueryService()throws Exception{
try {
System.out.println("Querying Active Directory Using Java");
System.out.println("------------------------------------");
String domain = "abc.com";
String url = "ldap.abc.com:389";
String username = "username";
String password = "password";
String choice = "samaccountname";
String searchTerm = "xyz";
//Creating instance of ActiveDirectory
ActiveDirectory activeDirectory = new ActiveDirectory(username, password, domain, url);
//Searching
NamingEnumeration<SearchResult> result = activeDirectory.searchUser(searchTerm, choice, null);
while (result.hasMore()) {
SearchResult rs = (SearchResult) result.next();
Attributes attrs = rs.getAttributes();
String temp = attrs.get("samaccountname").toString();
System.out.println("Username : " + temp.substring(temp.indexOf(":") + 1));
String memberOf = attrs.get("memberOf").toString();
String stringToSearch = "CN=App_abc_Admin";
boolean test = memberOf.toLowerCase().contains(stringToSearch.toLowerCase());
if(test){
String mail = attrs.get("mail").toString();
System.out.println("Email ID : " + mail.substring(mail.indexOf(":") + 1));
}
}
activeDirectory.closeLdapConnection();
}catch(Exception e){
}
}
ActiveDirectory.java
public class ActiveDirectory {
//required private variables
private Properties properties;
private DirContext dirContext;
private SearchControls searchCtls;
private String[] returnAttributes = { "*"};
private String domainBase;
private String baseFilter = "(&((&(objectCategory=Person)(objectClass=User)))";
public ActiveDirectory(String username, String password, String domainController,String url) {
properties = new Properties();
properties.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
properties.put(Context.PROVIDER_URL, "LDAP://" + url);
properties.put(Context.SECURITY_PRINCIPAL, username + "@" + domainController);
properties.put(Context.SECURITY_CREDENTIALS, password);
//initializing active directory LDAP connection
try {
dirContext = new InitialDirContext(properties);
} catch (NamingException e) {
//LOG.severe(e.getMessage());
//e.printStackTrace();
}
//default domain base for search
domainBase = getDomainBase(domainController);
//initializing search controls
searchCtls = new SearchControls();
searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
searchCtls.setReturningAttributes(returnAttributes);
}
public NamingEnumeration<SearchResult> searchUser(String searchValue, String searchBy, String searchBase) throws NamingException {
String filter = getFilter(searchValue, searchBy);
String base = (null == searchBase) ? domainBase : getDomainBase(searchBase);
return this.dirContext.search(base, filter, this.searchCtls);
}
public void closeLdapConnection(){
try {
if(dirContext != null)
dirContext.close();
}
catch (NamingException e) {
//e.printStackTrace();
}
}
private String getFilter(String searchValue, String searchBy) {
String filter = this.baseFilter;
if(searchBy.equals("email")) {
filter += "(mail=" + searchValue + "))";
} else if(searchBy.equals("username")) {
filter += "(samaccountname=" + searchValue + "))";
}else if(searchBy.equals("title")) {
filter += "(title=" + searchValue + "))";
}else if(searchBy.equals("department")) {
filter += "(department=" + searchValue + "))";
}else if(searchBy.equals("givenname")) {
filter += "(givenname=" + searchValue + "))";
}
else if(searchBy.equals("samaccountname")) {
filter += "(samaccountname=" + searchValue + "))";
}
return filter;
}
private static String getDomainBase(String base) {
char[] namePair = base.toUpperCase().toCharArray();
String dn = "DC=";
for (int i = 0; i < namePair.length; i++) {
if (namePair[i] == '.') {
dn += ",DC=" + namePair[++i];
} else {
dn += namePair[i];
}
}
return dn;
}
}
在上面的例子中,我通过搜索和搜索词。但是如何在memberOf属性中获取基于CN的用户列表?
我尝试更新过滤器,如下所示,但没有输出
private String baseFilter = "(&(objectClass=Person)(memberOf=cn=App_abc_Admin,ou=Application Groups,dc=abc,dc=com))";
答案 0 :(得分:0)
更新了过滤器,如下所示。现在可以使用
private String baseFilter = "(&((&(objectCategory=Person)(objectClass=User)(mail=*abc.com)(memberOf=CN=App_abc_Admin,OU=Application Groups,OU=Security Groups,OU=Users_OU,DC=abc,DC=com))))";