Question

控制器

public function getSearch(Request $request)
{

  $search = $request->input('search');


  $clients = Client::search($search)
                   ->paginate(5);


  $bankings = Banking::search($search)
                  ->paginate(5);

  return view('search/search',compact(['clients','bankings'])); 

}

查看

@extends('layouts.master')

@section('content')

    <div class="content">
      <div class="row search">
        <div class="col-xs-12">
          <div class="box" >
            <div class="box-body" >
               <table class="table table-bordered table-hover" id="clients">
                    <thead>
                           <th>Customer Code</th>
                           <th>Surname</th>
                           <th>Name</th>
                           <th>Company Name</th>
                           <th>ID Number</th>
                           <th>Email</th>
                           <th>Client Type</th>
                           <th>Created </th>
                    </thead>
                    @foreach($clients as $client)
                    <tr>
                        <td>{{$client->customercode}}</td>
                        <td>{{$client->name}}</td>
                        <td>{{$client->surname}}</td>
                        <td>{{$client->companyname}}</td>
                        <td>{{$client->idnumber}}</td>
                        <td>{{$client->email}}</td>
                        <td>{{$client->clienttype}}</td>
                        <td>{{$client->created_at}}</td>
                    </tr>  
                    @endforeach 
               </table>
               {{$clients->appends(Request::except('page'))->links()}}
            </div>
          </div>
         </div>
        </div>
       </div>


    <div class="content">
      <div class="row search">
        <div class="col-xs-12">
          <div class="box" >
            <div class="box-body" >
               <table class="table table-bordered table-hover" id="bankings">
                    <thead>
                           <th>Customer Code</th>
                           <th>Account Holder's Name</th>
                           <th>Bank</th>
                           <th>Account Type</th>
                           <th>Account Number</th>
                    </thead>
                    @foreach($bankings as $banking)
                    <tr>
                        <td>{{$banking->customercode}}</td>
                        <td>{{$banking->acc_holders_name}}</td>
                        <td>{{$banking->bank}}</td>
                        <td>{{$banking->acc_type}}</td>
                        <td>{{$banking->acc_no}}</td>
                    </tr>  
                    @endforeach 
               </table>
               {{$bankings->appends(Request::except('page2'))->links()}}
            </div>
          </div>
         </div>
        </div>
       </div>

@stop

所以我有一个搜索功能，通过2个表，即客户端＆amp;银行根据用户输入进行搜索，并返回与输入匹配的结果。所以我在两个表上添加了简单的laravel分页。我的问题是，当我点击客户端表结果上的第2页时，它还会对Bankings表结果进行分页。我怎么能让它一次只分页一个表而不是两个？请帮忙

Answer 1

您可以添加＆＃39;名称＆＃39;你分页的事情：

在网址中，它现在是?clients=1&bankings=3等。

public function getSearch(Request $request)
{

    $search = $request->input('search');

    $clients = Client::search($search)
                      ->paginate(5, ['*'], 'clients');

    $bankings = Banking::search($search)
                        ->paginate(5, ['*'], 'bankings');

    return view('search/search',compact(['clients','bankings'])); 
}

https://laravel.com/api/5.5/Illuminate/Database/Eloquent/Builder.html#method_paginate

2个独立桌子上的分页

1 个答案: