这是我第一次运行浓缩咖啡而且我遇到了这个问题
问题:: android.support.test.espresso.NoMatchingViewException:找不到匹配的层次结构中的视图:(带有id:edu.gatech.seclass.sdpguessit:id / login_page_username_field并带有文本:是“输入用户名”,而父级Child的位置为1的Child父级中的位置0,ID为:16908290,并在屏幕上显示给用户)
这是我的代码:
package edu.gatech.seclass.sdpguessit.ui;
import android.support.test.espresso.DataInteraction;
import android.support.test.espresso.ViewInteraction;
import android.support.test.rule.ActivityTestRule;
import android.support.test.runner.AndroidJUnit4;
import android.test.suitebuilder.annotation.LargeTest;
import android.view.View;
import android.view.ViewGroup;
import android.view.ViewParent;
import static android.support.test.InstrumentationRegistry.getInstrumentation;
import static android.support.test.espresso.Espresso.onData;
import static android.support.test.espresso.Espresso.onView;
import static android.support.test.espresso.Espresso.pressBack;
import static android.support.test.espresso.Espresso.openActionBarOverflowOrOptionsMenu;
import static android.support.test.espresso.action.ViewActions.*;
import static android.support.test.espresso.assertion.ViewAssertions.*;
import static android.support.test.espresso.matcher.ViewMatchers.*;
import edu.gatech.seclass.sdpguessit.R;
import org.hamcrest.Description;
import org.hamcrest.Matcher;
import org.hamcrest.TypeSafeMatcher;
import org.hamcrest.core.IsInstanceOf;
import org.junit.Rule;
import org.junit.Test;
import org.junit.runner.RunWith;
import static org.hamcrest.Matchers.allOf;
import static org.hamcrest.Matchers.anything;
import static org.hamcrest.Matchers.is;
@LargeTest
@RunWith(AndroidJUnit4.class)
public class LoginActivityTest {
@Rule
public ActivityTestRule<LoginActivity> mActivityTestRule = new ActivityTestRule<>(LoginActivity.class);
@Test
public void loginActivityTest() {
ViewInteraction editText = onView(
allOf(withId(R.id.login_page_username_field), withText("Enter Username"),
childAtPosition(
childAtPosition(
withId(android.R.id.content),
0),
1),
isDisplayed()));
editText.check(matches(withText("Enter Username")));
ViewInteraction button = onView(
allOf(withId(R.id.login_button),
childAtPosition(
childAtPosition(
withId(android.R.id.content),
0),
2),
isDisplayed()));
button.check(matches(isDisplayed()));
ViewInteraction button2 = onView(
allOf(withId(R.id.create_player_button),
childAtPosition(
childAtPosition(
withId(android.R.id.content),
0),
3),
isDisplayed()));
button2.check(matches(isDisplayed()));
}
private static Matcher<View> childAtPosition(
final Matcher<View> parentMatcher, final int position) {
return new TypeSafeMatcher<View>() {
@Override
public void describeTo(Description description) {
description.appendText("Child at position " + position + " in parent ");
parentMatcher.describeTo(description);
}
@Override
public boolean matchesSafely(View view) {
ViewParent parent = view.getParent();
return parent instanceof ViewGroup && parentMatcher.matches(parent)
&& view.equals(((ViewGroup) parent).getChildAt(position));`enter code here`
}
};
}
}
我该如何解决这个问题?
答案 0 :(得分:0)
试试这个:
onView(withId(R.id.login_page_username_field)).check(matches(withText("Enter Username"));
答案 1 :(得分:0)
我在我的应用程序中显示了浮动操作按钮的ID时遇到了同样的问题,但在Espresso层次结构中却没有。
我结束了使用Android Studio中提供的 espresso测试记录器(单击“运行”,然后单击“记录Espresso测试”,然后按照您希望测试的方式浏览应用程序。 ..) 然后,您可以复制结果。
它缺乏优雅,但却能解决问题。