Grep只有Number文件中的最后4位数字

Question

仅从数字文件中获取最后4位数字。

$ cat test
12298700077
56198700770
23192604888
34198701041
89198701285
$ cat test | grep 0077
12298700077
56198700770

所需的输出就是这个

12298700077

Answer 1

使用正则表达式，特别是（<div class="card-body"> <table class="table"> <thead> <tr> <th>Photo</th> <th>Name</th> <th>Email</th> <th>Rating</th> <th >delete</th> </tr> </thead> <tbody> <tr *ngFor="let user of users | async"> <td > {{user.photoUrl}} </td> <td> {{user.userName}} </td> <td > {{user.email}} </td> <td> {{user.rating}}// Want this user rating as number into star rating </td> <td> {{user.id}} </td> <td> <button class="btn btn-sm btn-danger" (click)="onDelete(user.id)">delete</button> </td> </tr> </tbody> </table> </div> ）：＆＃39; $＆＃39; （匹配行尾的空字符串）：

man 7 regex