如何在javascript / JQuery中清除json对象值为空？

Question

var myObj;

myObj = [{ "name":"John", "age":30, "car":"maruti" },{ "name":"Smith", "age":50, "car":"indica" }];

我想得到json

[{ "name":"", "age":, "car":"" },{ "name":"", "age":, "car":"" }];

请解决此问题

Answer 1

只需使用map和for

即可

var myObj = [{ "name":"John", "age":30, "car":"maruti" },{ "name":"Smith", "age":50, "car":"indica" }];

var result = myObj.map(v=>{
   v = Object.assign({}, v);
   for( let k in v ) v[k] = "";
   return v;
});
	
console.log( result );

仅改变年龄。

var myObj = [{ "name":"John", "age":30, "car":"maruti" },{ "name":"Smith", "age":50, "car":"indica" }];
	
var result = myObj.map(v=>{
   v = Object.assign({}, v);
   v.age = "";
   return v;
});

console.log( result );

Answer 2

这是一个不会改变原始值的解决方案：

myObj.map(x => Object.keys(x).reduce((total, value) => { total[value] = ''; return total; }, {}));