Question

let fullString = "Hello world, there are \(string(07)) continents and \(string(195)) countries."
let range = [NSMakeRange(24,2), NSMakeRange(40,3)]

需要为整个字符串中的数字找到NSRange，并且两个数字都可能相同。目前如上所示的硬编码，消息可以是动态的，其中硬编码值将是有问题的。

我已拆分字符串并尝试获取NSRange，因为可能存在相同的值。比如stringOne和stringTwo。

func findNSMakeRange(initialString:String, fromString: String) {
        let fullStringRange = fromString.startIndex..<fromString.endIndex
        fromString.enumerateSubstrings(in: fullStringRange, options: NSString.EnumerationOptions.byWords) { (substring, substringRange, enclosingRange, stop) -> () in
            let start = distance(fromString.startIndex, substringRange.startIndex)
            let length = distance(substringRange.startIndex, substringRange.endIndex)
            let range = NSMakeRange(start, length)

            if (substring == initialString) {
                print(substring, range)
            }
        })
    }

收到Cannot invoke distance with an argument list of type (String.Index, String.Index)

等错误

任何人都有更好的解决方案吗？

Answer 1

另一种方法是定义一个扩展来返回一个范围数组，即[Range<String.Index>]：

extension StringProtocol where Index == String.Index {
    func ranges<T: StringProtocol>(of string: T, options: String.CompareOptions = []) -> [Range<Index>] {
        var ranges: [Range<Index>] = []
        var start: Index = startIndex

        while let range = range(of: string, options: options, range: start..<endIndex) {
            ranges.append(range)
            start = range.upperBound
        }

        return ranges
    }
}

然后你可以像这样使用它：

let string = "Hello world, there are 09 continents and 195 countries."
let ranges = string.ranges(of: "[0-9]+", options: .regularExpression)

因此，例如，如果您想在某些属性字符串中将这些数字加粗：

string.ranges(of: "[0-9]+", options: .regularExpression)
    .map { NSRange($0, in: string) }
    .forEach {
        attributedString.setAttributes(boldAttributes, range: $0)
}

如何从完整字符串iOS swift中为字符串查找多个NSRange

1 个答案: