Question

所以我有一个带有'date'列的pandas数据帧。我们的日历基于7月1日是第一天。我知道我可以做df ['date']。dt.week，但这给了我从1月1日开始的一周。有没有办法拿我的df并创建一个新的专栏'week'，其中'week'为0 7月的第一天到周日，然后是1 ......等等？基本上与dt.week的工作原理相同......只是转移到了7月1日。我知道重新采样允许我这样移动，我似乎无法弄清楚如何将它全部正确地作为列。

由于

更新：目前这样做......不完全正常。

def get_academic_year(x):
    if (x.month < 7):
        year = x.year - 1
    else:
        year = x.year
    return year

def get_week(x):
    return ((x['date'].week - 
    pd.to_datetime(pd.datetime(x['academic_year'], 7, 1)).week) % 52)

df_x['academic_year'] = df_x['date'].apply(lambda x: get_academic_year(x))
df_x['week'] = df_x.apply(lambda x: get_week(x), axis=1)

我的数据集：

'{"date":{"0":1414368000000,"1":1414454400000,"2":1414540800000,"3":1414627200000,"4":1414713600000,"5":1414800000000,"6":1414886400000,"7":1425254400000,"8":1425340800000,"9":1425427200000,"10":1425513600000,"11":1425600000000,"12":1425686400000,"13":1425772800000,"14":1433116800000,"15":1433203200000,"16":1433289600000,"17":1433376000000,"18":1433462400000,"19":1433548800000,"20":1433635200000,"21":1444262400000,"22":1444348800000,"23":1444608000000,"24":1444694400000,"25":1444780800000,"26":1444867200000,"27":1444953600000,"28":1445040000000,"29":1445126400000,"30":1452643200000,"31":1452729600000,"32":1452816000000,"33":1452902400000,"34":1452988800000,"35":1460505600000,"36":1460937600000,"37":1461024000000,"38":1461110400000,"39":1461196800000,"40":1461283200000,"41":1461369600000,"42":1461456000000,"43":1465776000000,"44":1465862400000,"45":1465948800000,"46":1466035200000,"47":1466121600000,"48":1470873600000,"49":1470960000000,"50":1471219200000,"51":1471305600000,"52":1471392000000,"53":1486598400000,"54":1489968000000,"55":1490054400000,"56":1490140800000,"57":1490227200000,"58":1490313600000,"59":1492387200000,"60":1492473600000,"61":1492560000000,"62":1492646400000,"63":1492732800000,"64":1494201600000,"65":1494288000000,"66":1494374400000,"67":1494460800000,"68":1494547200000,"69":1502668800000,"70":1502755200000,"71":1502841600000,"72":1502928000000,"73":1503014400000,"74":1503100800000,"75":1503187200000,"76":1505174400000,"77":1505433600000,"78":1507507200000,"79":1507593600000,"80":1507680000000,"81":1507766400000,"82":1507852800000,"83":1507939200000,"84":1508025600000,"85":1508976000000,"86":1509062400000,"87":1509148800000,"88":1509235200000,"89":1509321600000,"90":1509408000000,"91":1512086400000,"92":1524268800000,"93":1524355200000,"94":1529884800000,"95":1529971200000,"96":1530057600000,"97":1530144000000,"98":1530230400000}}'

更新＃2：

def get_academic_year(x):
    if (x.month < 7):
        year = x.year - 1
    else:
        year = x.year
    return year

def get_week(x):
    return int(((x['date'] - pd.to_datetime(pd.datetime(x['academic_year'], 7, 1)))).days / 7) + 1

rng = pd.date_range('7/1/2015', periods=365*3, freq='D')
df_x = pd.DataFrame()
df_x['date'] = rng
df_x['academic_year'] = df_x['date'].apply(lambda x: get_academic_year(x))
df_x['week'] = df_x.apply(lambda x: get_week(x), axis=1)
df_x

Answer 1

这可能适合你。

curl: no URL specified!

7月1日起的熊猫周年

1 个答案: