给定的两个数据表(tbl_A
和tbl_B
),我想在选择所有的行中的tbl_A
,其具有在tbl_B
,和我希望代码具有表现力。如果为data.tables定义了%in%
运算符,那么这样的事情将是理想的:
subset <- tbl_A[tbl_A %in% tbl_B]
我可以想出很多方法来实现我想要的东西,例如:
# double negation (set differences)
subset <- tbl_A[!tbl_A[!tbl_B,1,keyby=a]]
# nomatch with keyby and this annoying `[,V1:=NULL]` bit
subset <- tbl_B[,1,keyby=.(a=x)][,V1:=NULL][tbl_A,nomatch=0L]
# nomatch with !duplicated() and setnames()
subset <- tbl_B[!duplicated(tbl_B),.(x)][tbl_A,nomatch=0L]; setnames(subset,"x","a")
# nomatch with !unique() and setnames()
subset <- unique(tbl_B)[,.(x)][tbl_A,nomatch=0L]; setnames(subset,"x","a")
# use of a temporary variable (Thanks @Frank)
subset <- tbl_A[, found := FALSE][tbl_B, found := TRUE][(found)][,found:=NULL][]
但每个表达式都难以阅读,乍看之下代码的作用并不明显。有没有更惯用/表达的方式来完成这项任务?
出于示例的目的,这里有一些玩具data.tables:
# toy tables
tbl_A <- data.table(a=letters[1:5],
b=1:5,
c=rnorm(5))
tbl_B <- data.table(x=letters[3:7],
y=13:17,
z=rnorm(5))
# both tables might have multiple rows with the same key fields.
tbl_A <- rbind(tbl_A,tbl_A)
tbl_B <- rbind(tbl_B,tbl_B)
setkey(tbl_A,a)
setkey(tbl_B,x)
以及包含tbl_A
中与tbl_B
中至少一行匹配的行的预期结果:
a b c
1: c 3 -0.5403072
2: c 3 -0.5403072
3: d 4 -1.3353621
4: d 4 -1.3353621
5: e 5 1.1811730
6: e 5 1.1811730
答案 0 :(得分:1)
再添加2个选项
tbl_A[fintersect(tbl_A[,.(a)], tbl_B[,.(a=x)])]
和
tbl_A[unique(tbl_A[tbl_B, nomatch=0L, which=TRUE])]
答案 1 :(得分:0)
我不确定它是多么富有表现力(如果没有道歉),但这似乎有效:
tbl_A[,.(a,b,c,any(a == tbl_B[,x])), by = a][V4==TRUE,.(a,b,c)]
我确信它可以改进 - 我昨天才发现任何()并且仍在测试它:)