Question

我正在开发word scramble android app。我想以序列顺序显示单词的字符串，但在下面的代码中，它从字典中获取随机单词。我的问题是如何更改我的代码以从序列顺序中的字典中获取单词？

String[] dictionary=
{"One","Server","Terminate","Analyze","Finish","Start","Wonder","Slow"};

r = new Random(System.currentTimeMillis());
newGame();

// shuffle algorithm
private String shuffleWord(String word){

    List<String>  letters = Arrays.asList(word.split(""));
    Collections.shuffle(letters);
    String Shuffled="";
    for (String letter : letters ){
        Shuffled += letter;

    }
    return Shuffled;
}

private void  newGame(){
    // get random word from dictionary
    currentWord= dictionary[r.nextInt(dictionary.length)];

    // show the shuffled word
    tv_word.setText(shuffleWord(currentWord));

    // clear the textfield
    et_guess.setText("");

    // switch buttons
    b_new.setEnabled(false);
    b_check.setEnabled(true);

   }
}

Answer 1

其实你用随机位置选择你的单词

 r = new Random(System.currentTimeMillis());

使用从0到ArrayOfWords长度的随机整数。

currentWord= dictionary[r.nextInt(dictionary.length)];

为什么你不尝试制作一个计数器呢？

int r = 0;
while (r<dictionary.length()) {
currentWord = dictionary[r];
r++; 
}

或者我不明白你的答案。但是我理解的是假的。

如何将Random随机更改为Sequence Sequence

1 个答案: