我正在尝试扫描列名为S3KeyID的值,我正在寻找值“newkey”。
当我在测试中运行它时,它扫描dynamoDB表中的所有3个项目,它找到3个结果,没有匹配。
import boto3
import json
import decimal
import calendar
import datetime
from boto3.dynamodb.conditions import Key, Attr
def lambda_handler(event, context):
StartDateTime = datetime.datetime.now() - datetime.timedelta(minutes=10000)
EndDateTime = datetime.datetime.now()
# Helper class to convert a DynamoDB item to JSON.
class DecimalEncoder(json.JSONEncoder):
def default(self, o):
if isinstance(o, decimal.Decimal):
return str(o)
return super(DecimalEncoder, self).default(o)
dynamodb = boto3.resource('dynamodb')
table = dynamodb.Table('Overwatch')
print("Overwatch old messages")
response = table.scan(
#ExpressionAttributeNames = {'ST' : 'S3KeyID'},
FilterExpression = "S3KeyID = :key",
ExpressionAttributeValues =
{ #":dateStart": {"S": StartDateTime},
#":dateEnd": {"S": EndDateTime},
":key" : {"S" : "newkey"}
# ":S3KeyID : 1222433"
}
#ProjectionExpression="S3KeyID"
)
for i in response[u'Items']:
print(json.dumps(i, cls=DecimalEncoder))
return response
见结果:
Items": [],
"Count": 0,
"ScannedCount": 3,
答案 0 :(得分:1)
我想这样做会更好:
response = table.scan(
FilterExpression = Attr('S3KeyID').eq('newkey')
)
Read the docs了解更多示例。这是我的灵感:
同样,您可以根据项目的属性扫描表格。例如,这会扫描年龄小于27的所有用户:
response = table.scan(
FilterExpression=Attr('age').lt(27)
)
items = response['Items']
print(items)