我有这个SQL语句
SELECT
locales.id_c,
locales.name_p AS NombrePropietario,
locales.surname1 AS PrimerApellido,
locales.local_name AS Nombre_Local,
locales.zona AS ZonaLiga,
locales.id_m1 AS Maquina_1,
maquinas.tipo_m AS Tipo_de_Maquina1,
locales.id_m2 AS Maquina_2,
maquinas.tipo_m AS Tipo_de_Maquina2,
locales.id_m3 AS Maquina_3,
locales.id_m4 AS Maquina_4
FROM locales
INNER JOIN maquinas
ON locales.id_m1 = maquinas.id_m;
在这种情况下,它只显示了" Maquina_1"和" Tipo_de_Maquina1"
并且需要展示" Maquina_2"和" Tipo_de_Maquina2"," Maquina_3"和" Tipo_de_Maquina3"等等。
有人可以帮助我吗?
由于
答案 0 :(得分:1)
使用表别名加入maqinas表格多重:
SELECT
l.id_c,
l.name_p AS NombrePropietario,
l.surname1 AS PrimerApellido,
l.local_name AS Nombre_Local,
l.zona AS ZonaLiga,
l.id_m1 AS Maquina_1,
m1.tipo_m AS Tipo_de_Maquina1,
l.id_m2 AS Maquina_2,
m2.tipo_m AS Tipo_de_Maquina2,
l.id_m3 AS Maquina_3,
m3.tipo_m AS Tipo_de_Maquina3,
l.id_m4 AS Maquina_4,
m4.tipo_m AS Tipo_de_Maquina4
FROM locales l
LEFT JOIN maquinas m1 ON l.id_m1 = m1.id_m
LEFT JOIN maquinas m2 ON l.id_m2 = m2.id_m
LEFT JOIN maquinas m3 ON l.id_m3 = m3.id_m
LEFT JOIN maquinas m4 ON l.id_m4 = m4.id_m
;
如果记录没有maquina 1,2,3或4,我正在使用外部联接。如果每条记录都有所有maquinas,则可以切换到内部联接。
无论如何,您可能需要考虑另一个数据模型,在其中添加表locale_maquina
并从id_m1
表中删除单个id_m4
到locales
。这样可以更轻松地选择数据并支持链接到某个位置的灵活数量的maquinas。
答案 1 :(得分:0)
您的“Tipo_de_Maquina2”错误,因为它会显示“Tipo_de_Maquina1”的相同值。
您应该遵循“Tipo_de_Maquina1”的相同INNER JOIN
逻辑,以获取tipo_m
的其他值。
SELECT
locales.id_c,
locales.name_p AS NombrePropietario,
locales.surname1 AS PrimerApellido,
locales.local_name AS Nombre_Local,
locales.zona AS ZonaLiga,
locales.id_m1 AS Maquina_1,
m1.tipo_m AS Tipo_de_Maquina1,
locales.id_m2 AS Maquina_2,
m2.tipo_m AS Tipo_de_Maquina3,
locales.id_m3 AS Maquina_3,
m3.tipo_m AS Tipo_de_Maquina4,
locales.id_m4 AS Maquina_4,
m4.tipo_m AS Tipo_de_Maquina4
FROM locales
INNER JOIN maquinas AS m1
ON locales.id_m1 = m1.id_m
INNER JOIN maquinas AS m2
ON locales.id_m2 = m2.id_m
INNER JOIN maquinas AS m3
ON locales.id_m3 = m3.id_m
INNER JOIN maquinas AS m4
ON locales.id_m4 = m4.id_m;