awk用引号连接csv列

Question

我想连接一个csv文件的两列。我对csv的引用有somme问题。

"column one","column two","column three"
"A","1","A1"
"B","2","B2"
"C","3","C3"

我使用此命令行：

awk -F, '{$2=$3" - "$x;for(i=1;i<=NF;i++)if(i!=x)f=f?f FS $i:$i;print f;f=""}' x=3 file.csv

结果是：

"column one","column two"
"A","1" - "A1"
"B","2" - "B2"
"C","3" - "C3"

我想删除第二列“3 **” - “** C3”

的内部引号

Answer 1

使用GNU awk

$ awk -F, -v OFS=, 'NR==1{NF--} {print gensub(/","/," - ",2)}' file

"column one","column two"
"A","1 - A1"
"B","2 - B2"
"C","3 - C3"

第一行

，删除最后一个字段。否则用连字符替换带引号的逗号。

Answer 2

Awk 解决方案：

awk 'BEGIN{ FS=OFS="\042,\042" }{ $2=$2" - "$3; NF=2 }1' file.csv

输出：

"A","1 - A1"
"B","2 - B2"
"C","3 - C3"

Answer 3

Gnu sed：

kent$  cat f
"A","1","A1"
"B","2","B2"
"C","3","C3"

kent$  sed 's/","/ - /2' f
"A","1 - A1"
"B","2 - B2"
"C","3 - C3"

测试：

{{1}}