Question

Html代码：

<input type="file" class="form-control" name="video[]" placeholder=" Enter Image file">
<div><h2>OR</h2></div>
<input type="text" class="form-control" name="yurl" placeholder=" Enter youtube embedded code">
<button type='submit' name="save" class='btn btn-success waves-effect waves-light'><i class='fa fa-upload'></i> Save</button>

php代码：

<?php
if(isset($_POST['save'])){
    $yurl = ($_POST['yurl']); 
    $new_data=mysqli_real_escape_string($connection, stripslashes($yurl));
    echo $yurl;
    foreach($_FILES["video"]["tmp_name"] as $key=>$tmp_name){
        $temp = $_FILES["video"]["tmp_name"][$key];
        $name = $_FILES["video"]["name"][$key];
        if(empty($temp))
        {
            break;
        }

        move_uploaded_file($temp,"../uploads/galleryvideos/".$name); 
        $sql = "INSERT INTO gallaryvids (video ,youtube)
        VALUES ('$name', '$yurl')";

        if (mysqli_query($connection,$sql)) {
?>
        <script>
            window.location.href = "view_gal_video.php";

        </script>
<?php
        }
    }   
}

＆GT;

我要插入的网址：https://youtu.be/sA0-QXbLnaE

视频和链接都会插入当我只想插入链接而不是视频时，它会失败，但不会给出任何错误

Answer 1

使用数据库连接更新了代码。

if(isset($_POST['save'])){

$servername = "localhost";
$username = "root";
$password = "";
$dbname = "";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$yurl = $_POST['yurl'];
//$video='test';


foreach($_FILES["video"]["tmp_name"] as $key=>$tmp_name){
        $temp = $_FILES["video"]["tmp_name"][$key];
        $name = $_FILES["video"]["name"][$key];
        if(empty($temp))
        {
            break;
        }
        move_uploaded_file($temp,"../uploads/galleryvideos/".$name); 


$sql = "INSERT INTO gallaryvids (video, youtube)VALUES ('$name', '$yurl')";

if ($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
}

无法使用php在mysql数据库中插入url

1 个答案: