Question

我想知道为什么我找不到解决这个奇怪问题的方法。对不起，如果我看起来不对，但我非常绝望，并尽可能地解决这个问题。

在递归函数中，我收集sql数据并将它们存储在一个数组中。但是，当我使用print_r输出数组值时，我会得到如下奇怪的值：

A＆＃34; parentMale＆＃34; =＆＃39; 45273＆＃39;或者a。＆＃34; parentFemale＆＃34; =＆＃39; 44871＆＃39;要么一个＆＃34; parentMale＆＃34; =＆＃39; 7625＆＃39;或者a。＆＃34; parentFemale＆＃34; =＆＃39; 7481＆＃39; OR数组或数组 OR数组或数组或a。＆＃34; parentMale＆＃34; = ...

虽然我的功能如下：

    public function getSelfAndAncestorsShort($id) {
  $animalids = array();
  if ($id != "") 
  {
      $query = "SELECT a.\"parentMale\" AS sire, a.\"parentFemale\" AS dam
      FROM animals a
      WHERE a.id = ".$id;

      $res = pg_query($query);
      while ($row = pg_fetch_object($res)) 
      {
        if ($row->sire != "")
        $animalids[]  = "a.\"parentMale\" = '" .$row->sire ."'";
        if ($row->dam != "")
        $animalids[]  = "a.\"parentFemale\" = '" .$row->dam ."'";

        $animalids[] = $this->getSelfAndAncestorsShort($row->sire);
        $animalids[] = $this->getSelfAndAncestorsShort($row->dam);

        $animalids = implode (" OR ", $animalids);

      }

  }
  return $animalids;
}

我希望有人可以帮助我，因为我真的不知道。

Answer 1

如果$id为空，则函数返回一个数组。此外，在添加到$animalids数组之前，您不会检查函数的返回值：

public function getSelfAndAncestorsShort($id) {
  $animalids = array();
  if ($id != "")
  {
      $query = "SELECT a.\"parentMale\" AS sire, a.\"parentFemale\" AS dam
      FROM animals a
      WHERE a.id = ".$id;

      $res = pg_query($query);
      while ($row = pg_fetch_object($res))
      {
        if ($row->sire != "")
        $animalids[]  = "a.\"parentMale\" = '" .$row->sire ."'";
        if ($row->dam != "")
        $animalids[]  = "a.\"parentFemale\" = '" .$row->dam ."'";

        $val = $this->getSelfAndAncestorsShort($row->sire);
        if ($val) $animalids[] = $val; // Check here
        $val = $this->getSelfAndAncestorsShort($row->dam);
        if ($val) $animalids[] = $val; // Check here

      }

  }
  if (empty($animalids)) return "" ; // Check here
  return implode (" OR ", $animalids); // Only implode here
}

PHP数组有时会返回＆＃39;数组＆＃39;

1 个答案: