Question

我想要一个Java正则表达式：

ACK：2018-03-08 12：12：28：4802：RETN = 0，ID = 1，NUM = 9，RESULT = 290,1，＆＃34; sip：99990030@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990030＆＃34;，1,31,106，＆＃34; 0.0.0.0＆＃34;，0＆安培; 291,1，＆＃34; SIP：99990031@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990031＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 292,1，＆＃34; SIP：99990032@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990032＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 293,1，＆＃34; SIP：99990033@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990033＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 294,1，＆＃34; SIP：99990034@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990034＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 295,1，＆＃34; SIP：99990035@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990035＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 296,1，＆＃34; SIP：99990036@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990036＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 297,1，＆＃34; SIP：99990037@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990037＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 298,3，＆＃34; SIP：99990039@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＃＆34;，＆＃34; 99990039＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0 ACK：2018-03-08 12:12:28:4802：RETN = 0，ID = 1，NUM = 2，RESULT = 299,3，＆＃34; sip：99990038@192.30.32.68"，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990038＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0＆安培; 700,1，＆＃34; SIP：99990040@192.30.32.68" ;，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990040＆＃34;，1,31,101，＆＃34; 0.0.0.0＆＃34;，0

找到每个子字符串，如：

290,1，＆＃34; SIP：99990030@192.30.32.68"，＆＃34; **********＆＃34;＆＃34; ＆＃34;＆＃34; 99990030＆＃34;，1,31,106，＆＃34; 0.0.0.0＆＃34;，0

我试过

Pattern pattern1 = Pattern.compile("(\\d+),(\\d+),\"sip:(.+)\",.+,.+,\"(\\d+)\",.+,.+,.+,.+,.+?&");

但这不起作用。

编辑：根据回应我这样做了;

   Pattern pattern =Pattern.compile("(\\d+),(\\d+),\"sip:(.+)\",\".*\",\".*\",\"(\\d+)\",\\d+,\\d+,\\d+,\".*\",\\d+");
   Matcher matcher;
   String teststr="................";
   String[] test2=teststr.split("&");
   List<String> result=new ArrayList<>();
   for(String s:test2){
    matcher=pattern.matcher(s);
    if(matcher.find()) result.add(matcher.group(0));
   }
   result.forEach(System.out::println);

编辑2：弗朗西斯科的回应也很好。谢谢大家。

Answer 1

在JShell中进行测试很难看，但在Scala中，我们使用＆＃34;＆＃34;＆＃34;＆＃34;进行字符串屏蔽。一些多线串＆＃34;其中＆＃34;包含引号＆＃34;＆＃34;＆＃34;，所以我在那里做了：

val log = """ACK : 2018-03-08 12:12:28 : 4802 : RETN=0,ID=1,NUM=9,RESULT=290,1,"sip:99990030@192.30.32.68","**********"," ","99990030",1,31,106,"0.0.0.0",0&291,1,"sip:99990031@192.30.32.68","**********"," ","99990031",1,31,101,"0.0.0.0",0&292,1,"sip:99990032@192.30.32.68","**********"," ","99990032",1,31,101,"0.0.0.0",0&293,1,"sip:99990033@192.30.32.68","**********"," ","99990033",1,31,101,"0.0.0.0",0&294,1,"sip:99990034@192.30.32.68","**********"," ","99990034",1,31,101,"0.0.0.0",0&295,1,"sip:99990035@192.30.32.68","**********"," ","99990035",1,31,101,"0.0.0.0",0&296,1,"sip:99990036@192.30.32.68","**********"," ","99990036",1,31,101,"0.0.0.0",0&297,1,"sip:99990037@192.30.32.68","**********"," ","99990037",1,31,101,"0.0.0.0",0&298,3,"sip:99990039@192.30.32.68","**********"," ","99990039",1,31,101,"0.0.0.0",0 ACK : 2018-03-08 12:12:28 : 4802 : RETN=0,ID=1,NUM=2,RESULT=299,3,"sip:99990038@192.30.32.68","**********"," ","99990038",1,31,101,"0.0.0.0",0&700,1,"sip:99990040@192.30.32.68","**********"," ","99990040",1,31,101,"0.0.0.0",0""" 

val parts = log.split ("&")

val lines = parts.map (s=> s.replaceAll (".*RESULT=", "") 
lines.foreach (println)

结果：

290,1,"sip:99990030@192.30.32.68","**********"," ","99990030",1,31,106,"0.0.0.0",0
291,1,"sip:99990031@192.30.32.68","**********"," ","99990031",1,31,101,"0.0.0.0",0
292,1,"sip:99990032@192.30.32.68","**********"," ","99990032",1,31,101,"0.0.0.0",0
293,1,"sip:99990033@192.30.32.68","**********"," ","99990033",1,31,101,"0.0.0.0",0
294,1,"sip:99990034@192.30.32.68","**********"," ","99990034",1,31,101,"0.0.0.0",0
295,1,"sip:99990035@192.30.32.68","**********"," ","99990035",1,31,101,"0.0.0.0",0
296,1,"sip:99990036@192.30.32.68","**********"," ","99990036",1,31,101,"0.0.0.0",0
297,1,"sip:99990037@192.30.32.68","**********"," ","99990037",1,31,101,"0.0.0.0",0
299,3,"sip:99990038@192.30.32.68","**********"," ","99990038",1,31,101,"0.0.0.0",0
700,1,"sip:99990040@192.30.32.68","**********"," ","99990040",1,31,101,"0.0.0.0",0

这遵循＆＃34;使用可能有效的最简单的事情＆＃34;

Answer 2

我不认为你太过分了：

\d{3},\d,\"sip:\d{8}@\d{3}\.\d{1,3}\.\d{1,3}\.\d{1,3}","\*{10}","[" ]","\d{8}",\d,\d{2},\d{3},"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}",\d

现场演示here。

当然，要将其合并到Jave中，您可以使用

Pattern pattern1 = Pattern.compile(regularExpression, Pattern.LITERAL);

所以你不必逃避所有的反斜杠。

用于匹配字符串

2 个答案: