所选行之间的总差异

Question

我有一个如下所示的数据集

CREATE TABLE [dbo].[testTable](
[ID] [int] NULL,
[Type] [varchar](50) NULL,
[Time] [datetime] NULL)

 INSERT INTO testTable
(Id,Type,Time)
SELECT '1','Start','Feb 22 2018  6:02AM' UNION ALL
SELECT '1','Move','Feb 22 2018  7:10AM' UNION ALL
SELECT '1','End','Feb 22 2018  7:21AM' UNION ALL
SELECT '1','Idle','Feb 22 2018  7:31AM' UNION ALL
SELECT '1','Idle','Feb 22 2018  7:35AM' UNION ALL
SELECT '1','Start','Feb 22 2018  8:06AM' UNION ALL
SELECT '1','Move','Feb 22 2018  8:25AM' UNION ALL
SELECT '1','Move','Feb 22 2018  8:36AM' UNION ALL
SELECT '1','End','Feb 22 2018  8:48AM' UNION ALL
SELECT '1','Start','Feb 22 2018 10:06AM' 

我需要在当天的开始和结束之间获得TOTAL差异。如果Start在夜间持续，则截止时间应为00：00hrs。

实施例： - 它应该是（End-Start）+（End-Start）+（2018-02-23 00.00.00 - Start）。

可以一个接一个地输入2个开始（或结束）

Answer 1

这有点猜测，因为OP没有指定他们的预期结果。因此，我不知道＆＃34; EndTime - StartTime＆＃34;应该是（也许是几秒钟？我猜到的）。

同样，如果这不对，请发布预期结果并回复我的评论。我们不介意读者。 ：）

WITH Leads AS(
    SELECT ID,
           [Type],
           [Time],
           ISNULL(LEAD([Time]) OVER (PARTITION BY CONVERT(date, [Time]) ORDER BY [Time]), DATEADD(DAY, 1,CONVERT(date, [Time])))  AS NextTime
    FROM testTable
    WHERE [Type] in ('Start','End'))
SELECT ID,
       SUM(DATEDIFF(SECOND,[Time], NextTime)) AS TotalSeconds
FROM Leads
WHERE [Type] = 'Start'
GROUP BY ID;

编辑：值得注意的是，这也假设 2个开始（或结束）不会一个接一个地输入。样本数据并未表明发生了这种情况，但当然，这并不意味着真实数据是干净的。

Answer 2

尝试使用此替代解决方案，它不会使用def tell(receiver, message) do IO.puts "[#{inspect self}] Sending #{message} to #{inspect receiver}" send receiver, {:ok, self, message} end 或lead：

lag

Answer 3

您可以在GROUP BY查询中使用LAG（）函数，就像任何其他查询一样。唯一的区别是窗口中允许的列（OVER）和LAG中的列是GROUP BY后SELECT中允许的列：

示例表：

CREATE TEMP TABLE foo AS
SELECT date::date, session_id, upload_usage, download_usage, 
total_usage_on_a_day
FROM ( VALUES
( '10/21/2014', '0007994b', 37578561   , 6800209   , 44378770 ),
( '10/22/2014', '0007994b', 218113296  , 85272007  , 303385303 ),
( '10/23/2014', '0007994b', 552228616  , 252390680 , 804619296 ) ,
( '10/24/2014', '0007994b', 799772020  , 391196041 , 1190968061 ),
( '10/25/2014', '0007994b', 1047233978 , 529908804 , 1577142782 ),
( '10/26/2014', '0007994b', 1294608258 , 668515778 , 1963124036 ),
( '10/27/2014', '0007994b', 1066656794 , 557318645 , 2573613674 ),
( '10/27/2014', '00079e4e', 12949219   , 7265243   , 20214462 ),
( '10/28/2014', '00079e4e', 203871297  , 114308478 , 318179775 ),
( '10/29/2014', '00079e4e', 445466682  , 251486943 , 696953625 ),
( '10/30/2014', '00079e4e', 183499477  , 109643736 , 893143213 )
) AS t( date, session_id, upload_usage, download_usage, total_usage_on_a_day 
);

示例查询：

select 
date,
session_id, 
sum(upload_usage) as upload,
sum(download_usage) as download,
sum(total_usage_on_a_day) as total_as_cumm,
sum(total_usage_on_a_day) 
- coalesce(lag(sum(total_usage_on_a_day)) over (partition by session_id 
order by date), 0)
as expected_difference
from jiodba.s_crc_zda_mon_conn_usage 
where gpart = '1100043958' 
and zzaccess_ntwk_id = 'FTTH' 
group by session_id, date
order by session_id, date 
limit 100 ;