如何通过MS Graph创建事件,房间为位置?

时间:2018-03-08 03:14:57

标签: calendar office365 microsoft-graph

我正在尝试通过MS Graph创建一个事件,其中包含已在我的Outlook帐户中设置的空间。 但问题是,如果没有作为与会者添加房间,就无法预订房间。

如果我只将房间添加为位置,则不会通知并预订房间帐户中的日历。

{
  "subject": "Let's go picnicking",
  "body": {
    "contentType": "HTML",
    "content": "Does late morning work for you?"
  },
  "start": {
      "dateTime": "2018-03-20T12:00:00",
      "timeZone": "Pacific Standard Time"
  },
  "end": {
      "dateTime": "2018-03-20T14:00:00",
      "timeZone": "Pacific Standard Time"
  },
  "location":{
      "coordinates": {"@odata.type": "microsoft.graph.outlookGeoCoordinates"},
      "displayName":"RM.Papaya",
      "locationType": "conferenceRoom",
      "address": {"@odata.type": "microsoft.graph.physicalAddress"}
  },
  "locations": [
        {
            "displayName": "RM.Papaya",
            "locationType": "conferenceRoom"
        }
    ],
  "attendees": [
    {
      "emailAddress": {
        "address":"Matthew_Liao@Ginaworks.onmicrosoft.com",
        "name": "Matthew Liao"
      },
      "type": "required"
    }
  ]
}

但是,如果我还将房间添加为位置和与会者,则会通知房间帐户中的日历,但位置显示只是与房间帐户无关的文本。

{
  "subject": "Let's go picnicking",
  "body": {
    "contentType": "HTML",
    "content": "Does late morning work for you?"
  },
  "start": {
      "dateTime": "2018-03-20T12:00:00",
      "timeZone": "Pacific Standard Time"
  },
  "end": {
      "dateTime": "2018-03-20T14:00:00",
      "timeZone": "Pacific Standard Time"
  },
  "location":{
      "displayName":"RM.Papaya",
      "locationType": "conferenceRoom",
      "address": {"@odata.type": "microsoft.graph.physicalAddress"}
  },
  "locations": [
        {
            "displayName": "RM.Papaya",
            "locationType": "conferenceRoom"
        }
    ],
  "attendees": [
    {
      "emailAddress": {
        "address":"Matthew_Liao@Ginaworks.onmicrosoft.com",
        "name": "Matthew Liao"
      },
      "type": "required"
    },
    {
      "emailAddress": {
        "address":"rm.papaya@Ginaworks.onmicrosoft.com",
        "name": "RM.Papaya"
      },
      "type": "required"
    }
  ]
}

这是合理的还是合乎逻辑的? 或者我的代码中有任何错误? 谢谢你的帮助。

1 个答案:

答案 0 :(得分:0)

显示问题是API的限制。这是我们希望解决的问题,但是当发生这种情况时我无法猜测。