Question

好的我试图在Python中获取前一周的日期，假设周从星期日开始，到星期六结束。

通过谷歌和反复试验，我有这个：

def get_week_days(year, week):
    d = date(year,1,1)
    if(d.weekday()>3):
        d = d+timedelta(7-d.weekday())
    else:
        d = d - timedelta(d.weekday())
    dlt = timedelta(days = (week-1)*7)
    FH_start = d + dlt
    FH_end = d + dlt + timedelta(days=6)
    return FH_start, FH_end

print get_week_days(2018, this_week_int)

并且输出： (datetime.date(2018, 3, 5), datetime.date(2018, 3, 11))

我如何抵消星期日的星期开始，还是有更好的方法来写这个？

Answer 1

这是一个简单的版本：

from datetime import date, timedelta    
def get_week_days(year, week):

    year_start = date(year, 1, 1)

    # the following line assumes your this_week_int starts at 0
    # if this_week_int starts at 1, change to week-2

    week_start = year_start + timedelta(days=-year_start.isoweekday(), weeks=week-1)
    week_end = week_start + timedelta(days=6)

    return week_start, week_end

get_week_days(2018, 1)

# (datetime.date(2017, 12, 31), datetime.date(2018, 1, 6))

get_week_days(2018, 10)

# (datetime.date(2018, 3, 4), datetime.date(2018, 3, 10))

基本上，.isoweekday()周一返回1，星期日返回7，所以当你扣除工作日时，会给你星期日的开始。

Answer 2

你可以如下：

get

现在您有一周的开始和结束日期，您可以根据需要找到周日期。有关更多信息，请参阅this

在Python上获取上周的日期

2 个答案: