Question

我的主页列表中有20行来自我的数据库，现在我想创建另一个页面，当从主页单击链接时，将显示一条记录的完整详细信息，这是我的代码，显示20条记录：< / p>

<table class="table stats-table ">
    <thead>
        <tr>
            <th colspan="3">Latest Uploads</th>
        </tr>
    </thead>
    <tbody>
        <?php
            require_once 'dbconfig.php';
            $query = "SELECT musicID, musicName, musicUploader, musicDate FROM tbl_music ORDER BY musicDate DESC LIMIT 20";
            $stmt = $DBcon->prepare( $query );
            $stmt->execute();
            while ($row=$stmt->fetch(PDO::FETCH_ASSOC) ) {
            extract($row);
            ?>
            <tr>
                <td><?php echo $musicName; ?></td>
                <td align="center"><span class="label label-success"><em><b>By:</b> <?php echo $musicUploader; ?></em></span> &nbsp;&mdash;&nbsp;<?php echo $musicDate; ?></td>
                <td><h5><a href="music-details.php?music=<?php echo $musicID; ?>"><i class="fa fa-download"></i></a></h5></td>
            </tr>
            <?php
        }
        ?>
    </tbody>
</table>

所以请不要知道该怎么做 music-details.php 我需要帮助的页面。

提前致谢

Answer 1

像这样

fn2

Answer 2

我找到了这个问题的工作答案，它确实解决了我的新代码问题：

<?php
$mysql_hostname = 'sql106.epizy.com';
$mysql_username = 'epiz_21612479';
$mysql_password = 'HPpc47590656';
$mysql_dbname = 'epiz_21612479_db';

$music = $_GET['music'];

try {

$pdo= new PDO("mysql:host=$mysql_hostname;dbname=$mysql_dbname", $mysql_username, $mysql_password); 
     $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (PDOException $e) {
     exit( $e->getMessage() );
}


try {

$stmt = $pdo->prepare('SELECT * FROM tbl_music WHERE musicID = :id');
$stmt->bindParam(':id', $music);
$stmt->execute();

} catch (PDOException $e) {
     echo $e->getMessage();
}

/* optional method
foreach($stmt as $row) {
      echo $row['id'] . ' ' . $row['name'] . ' ' . $row['email'];
}
*/

while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
  $id = $row['musicID'];
  $mn = $row['musicName'];
  $ma = $row['musicArtist'];
  $mu = $row['musicUploader'];
  $mf = $row['musicFile'];
  $ms = $row['musicSize'];
  $md = $row['musicDate'];
}


?>

以下是详细信息的显示位置：

艺术家：

        <p><b>Uploader:</b> <?php echo $mu; ?></p>
        <p><b>Size:</b> <?php echo $ms; ?></p>
        <p><b>Date  Uploaded:</b> <?php echo $md; ?></p>
        <a href="downloads/<?php echo $mf; ?>" title="Downloadnow" class='btn btn-sm btn-danger'><i class="fa fa-cloud-download"></i> Download </a>

感谢所有试图帮助我的人，我也从stackoverflow得到了答案答案在这里How to retrieve details for a particular id from MYSQL database

如何使用url中的唯一ID选择行

2 个答案: