CompSciLab1.exe中0x013DC813处的未处理异常：0xC0000005：访问冲突读取位置0xCCCCCD3C。发生了

Question

当程序在从文件读取后尝试打印出文件内容时，我一直收到此错误。我的程序能够从文件中读取，但无法将文件中的内容打印到屏幕上。我还想将数据作为指针传递，以便稍后在程序中对数据进行排序，但我的printFile函数给我带来了问题。我的文本文件位于.cpp程序所在的位置。我不确定错误在哪里。

#include <iostream>
#include <cstdlib>
#include <fstream>
#include <iomanip>
#include <string>
using namespace std;

const int MAX_SIZE = 50;
struct stdRec
{
    string fname, lname, email, id;
    double gpa;
};

void mainMenu();
void readFile(int & count, stdRec Stud[], stdRec *pStud[]);
void printFile(int count, stdRec *pStud[]);
//void sort(stdRec *pStud[], int & count, int & choice); //ignore

int main()
{
    int choice = 0;
    int count = 1;
    stdRec Students[MAX_SIZE];
    stdRec *pStudents[MAX_SIZE];
    readFile(count, Students, pStudents);
    do
    {
        mainMenu();
        cin >> choice;

        switch (choice)
        {
            case 1:
            {
                printFile(count, pStudents);
                break;
            }
            case 7:
            {
                cout << "\nBye!\n";
                break;
            }
                /*case 2:
                 case 3:
                 case 4:
                 case 5:
                 case 6:
                 {
                 sort(pStudents, count, choice);
                 break;
                 }*/
            default:
            {
                cout << "Invalid entry, try again.";
            }

        }
    } while (choice != 7);
    system("pause");
    return 0;
}

void mainMenu()
{
    cout << "\n\t\tMain Menu\n\n" << "1. Print records.\n" //opens and prints unsorted from the file
            << "2. Sort by id.\n" //sorts by id
            << "3. Sort by first name.\n" //sorts by first name
            << "4. Sort by last name.\n" //sorts by last name
            << "5. Sort by email.\n" //sorts by email
            << "6. Sort by gpa.\n" // sorts by gpa
            << "7. Exit.\n"; //exit the program
}

void readFile(int & count, stdRec Stud[], stdRec *pStud[])
{
    ifstream myfile; // text file is called "recordsample"
    myfile.open(("recordsample.txt"));
    if (!myfile)
    {
        cout << "Cannot open file, terminating program." << endl;
        exit(1);
    }
    while (!myfile.eof() && count < MAX_SIZE)
    {
        myfile >> Stud[count].id >> Stud[count].fname >> Stud[count].lname
                >> Stud[count].email >> Stud[count].gpa;
        pStud[count] = &Stud[count];
        count++;
    }
    myfile.close();
}

void printFile(int count, stdRec *pStud[])
{
    cout << pStud[count]->id << "\t" << pStud[count]->fname << "\t"
            << pStud[count]->lname << "\t" << pStud[count]->email << "\t"
            << pStud[count]->gpa << endl;
    count++;
}

recordsample.txt

7196478     Mary        Jones       mary.jones@gmail.com        3.9
3939724     John        Lee         john.lee@gmail.com          3.5
0943567     Ashley      Smith       ashley.smith@gmail.com      2.9 
2374598     Mark        Williams    mark.williams@gmail.com     3.3