Question

我有一个看起来像这样的表：

user_id   user_action      timestamp
1         action #2     2016-02-01 00:02  
2         action #1     2017-10-05 15:24
3         action #3     2017-03-31 19:35
4         action #1     2017-07-09 00:24
1         action #1     2018-11-05 18:28
1         action #3     2018-02-01 13:02
2         action #2     2017-10-05 16:14
2         action #3     2017-10-05 16:34
etc

我的任务是编写一个查询，在那里我可以看到用户会话，其中用户按特定顺序执行操作＃1,2和3，操作之间的时间间隔小于一小时。例如，用户＃2有一个会话

2         action #1     2017-10-05 15:24
2         action #2     2017-10-05 16:14
2         action #3     2017-10-05 16:34

很抱歉没有我自己的尝试，因为我真的被卡住了，不知道，从哪里开始。提前谢谢！

Answer 1

这可以通过窗口函数lead和lag完成，它们可以分别获取下一行和上一行的值。

select distinct user_id
from (select user_id,user_action,timestamp,
      lag(user_action) over(partition by user_id order by timestamp) as prev_action,
      lead(user_action) over(partition by user_id order by timestamp) as next_action,
      datediff(minute,lag(timestamp) over(partition by user_id order by timestamp),timestamp) as time_diff_with_prev_action,
      datediff(minute,timestamp,lead(timestamp) over(partition by user_id order by timestamp)) as time_diff_with_next_action
      from tbl
     ) t
where user_action='action#2' and prev_action='action#1' and next_action='action#3'
and time_diff_with_prev_action <= 60 and time_diff_with_next_action <= 60

具有特定用户操作顺序的SQL查询

1 个答案: