Question

以下是我的代码：

  $sql = "SELECT count(EventCode) as Total_Event FROM sample where Age between 5 and 10";
  $stmt = sqlsrv_query( $conn, $sql )

  $sql1 = "SELECT count(EventCode) as Total_Event FROM sample where Age between 50 and 80";
  $stmt1 = sqlsrv_query( $conn, $sql1 );

从上面的查询中，我可以计算sql和sql1语句发生的事件数。

我需要对这两个查询值sql和sql1

取平均值

请帮助我如何更改我的代码以实现它。

Answer 1

您希望两个不同年龄段的人的平均事件数量。这真的很奇怪，但最简单的方法是单个查询：

SELECT count(EventCode) / 2 as strange_average_calculation
FROM sample 
WHERE Age between 5 and 10 OR Age between 50 and 80;

Answer 2

你可以使用sql函数，即SELECT AVG(column_name)

  $sql = "SELECT AVG(EventCode) as avg_Event FROM sample where Age between 5 and 10";
  $stmt = sqlsrv_query( $conn, $sql )

  $sql1 = "SELECT AVG(EventCode) as avg_Event_2 FROM sample where Age between 50 and 80";
  $stmt = sqlsrv_query( $conn, $sql1 );

如何使用php查找两个不同的sql查询的平均值

2 个答案: