我需要使用Java程序从MySQL数据库中检索最后2分钟的数据吗?我不知道如何编写查询以获取特定时间间隔内的数据并引用了很多,但我没有找到正确的查询?任何人都可以帮帮我吗?
下面是我的Java程序,它连接到MySQL数据库,它有查询但该查询不起作用并抛出SQLSyntaxErrorException。
public static void main(String[] args)
{
String qry = "SELECT * FROM test.api WHERE EndTime = SELECT max(time) - interval 2 minute";
String url = "jdbc:mysql://localhost:3306";
String user = "root";
String password = "root@123";
Connection conn = null;
try
{
conn = DriverManager.getConnection(url, user, password);
PreparedStatement pstmt = conn.prepareStatement(qry);
ResultSet rs = pstmt.executeQuery();
while(rs.next())
{
String Name = rs.getString("Name");
String time = rs.getString("EndTime");
System.out.println(time);
System.out.println(Name);
}
}
catch (SQLException e)
{
e.printStackTrace();
}
finally
{
if(conn != null)
{
try
{
conn.close();
System.out.println("---Connection closed successfully---");
}
catch (SQLException e)
{
e.printStackTrace();
}
}
}
}
答案 0 :(得分:0)
不要使用max(时间)而是使用now()
String qry = "SELECT * FROM test.api WHERE EndTime = date_sub(now(), interval 2 minute)";
答案 1 :(得分:0)
试试这个:
-- suppose your data source time coincides with your storage server time
-- so to get the time 2 minutes ago should be like
SELECT * FROM test.api WHERE EndTime >= now() - interval 2 minute;
-- suppose your data source time is 60 behind your storage server time
-- so to get the time 2 minutes ago should be like
SELECT * FROM test.api WHERE EndTime >= now() - interval (2 + 60) minute;
-- suppose your data source time is 60 infront of your storage server time
-- so to get the time 2 minutes ago should be like
SELECT * FROM test.api WHERE EndTime >= now() - interval (2 - 60) minute;
因此,您必须知道两次之间的时差并使用上面提出的相应查询。
答案 2 :(得分:0)
String qry = "SELECT * FROM test.api WHERE EndTime > date_sub(now(),interval 2 MINUTE) ";