将非托管char **封送到托管字符串[]

时间:2011-02-06 17:46:08

标签: c# c++ string marshalling

我在DLL文件中有一个C ++函数(它使用多字节字符集选项编译):

_declspec(dllexport) void TestArray(char** OutBuff,int Count,int MaxLength)
{
    for(int i=0;i<Count;i++)
    {
        char buff[25];
        _itoa(i,buff,10);

        strncpy(OutBuff[i],buff,MaxLength);
    }
}

我认为C#原型必须是下一个:

    [DllImport("StringsScetch.dll", CharSet = CharSet.Ansi, CallingConvention = CallingConvention.Cdecl)]
    private static extern void TestArray([MarshalAs(UnmanagedType.LPArray)] IntPtr[] OutBuff, int Count, int MaxLength);

但是我应该准备IntPtr对象来接收来自非托管代码的字符串吗?

1 个答案:

答案 0 :(得分:4)

所以OutBuff基本上是一个指针数组 - 所以你需要创建一个IntPtr数组,其元素是有效的指针 - 即指向有效内存的IntPtr值。如下所示:

int count = 10;
int maxLen = 25;
IntPtr[] buffer = new IntPtr[count];

for (int i = 0; i < count; i++)
    buffer[i] = Marshal.AllocHGlobal(maxLen);

TestArray(buffer, count, maxLen);

string[] output = new string[count];
for (int i = 0; i < count; i++)
{
    output[i] = Marshal.PtrToStringAnsi(buffer[i]);
    Marshal.FreeHGlobal(buffer[i]);
}