Question

//this code is to compare two files and delet stop list word from file algorithm    
FileReader reader = new FileReader("C:\\Users\\Sara\\Desktop\\IRP\\Information Retrieval\\Algorithm.txt");
BufferedReader bufferedReader = new BufferedReader(reader);
FileReader readerStopList = new FileReader("C:/Users/Sara/Desktop/IRP/stopwords2.txt");
BufferedReader bufferedReaderStopList = new BufferedReader(readerStopList);
String word, stopword, newWord = "";
while ((word = bufferedReader.readLine()) != null) {
    for (int k = 0; k < word.split(" ").length; k++) {
        int count = 0;
        newWord = word.split(" ")[k];
        int n = newWord.length();
        if (n > 2) { //this statment to skip words of length 2
            while ((stopword = bufferedReaderStopList.readLine()) != null) {

                for (int j = 0; j < stopword.split(" ").length; j++) {

                    if (newWord.equalsIgnoreCase(stopword.split(" ")[j])) {
                        count++;

                    }
                }
            }
            if (count == 0) {
                System.out.println(newWord);

            }
        }

    }

Answer 1

我们假设n＆gt; 2是真的一次，然后你读取bufferedReaderStopList中的所有行，直到你到达EOF。这意味着每当n> 2再次为真，永远不会输入bufferedReaderStopList上的内部循环，因为readLine（）从现在开始总是返回null。

对于初学者，您的代码需要更好地构建，至少首先将bufferedReaderStopList的内容添加到数组中。还要避免多次对单词串进行拆分。做一次，然后使用生成的数组。

为什么我的if条件不起作用（if（n> 2））？

1 个答案: