我正在尝试循环查看包含我所有琐事问题的Div列表。我知道如何使用迭代器循环遍历所有这些,但我只想知道如何获取一个Div,运行一些代码,然后在用户单击提交后循环到数组中的下一个对象,然后运行相同的代码等我也隐藏了每个div,所以他们一次只能看到一个Div,直到他们完成上一个问题。 Java Script非常新,并且尽可能快地学习,任何提示都会非常感激
<div class="row">
<div class="col-12 questions">
<form name="quiz" onsubmit="return false">
<div class="q1">
<h1>The 'Mountain' is the nickname for which character?</h1>
<input type="radio" name="q" value="wrong" id="q1a">a. Gerold Clegane
<br>
<input type="radio" name="q" value="wrong" id="q1b">b. Sandor clegane
<br>
<input type="radio" name="q" value="wrong" id="q1c">c. Oberyn Martell
<br>
<input type="radio" name="q" value="correct" id="q1d">d. Gregor Clegane
<br>
<button class="submit" type="submit">Submit</button>
</div>
<div class="q2">
<h2>Who is the youngest child of Lord Tywin Lannister?</h2>
<input type="radio" name="q" value="correct" id="q2a">a. Tyrion Lannister
<br>
<input type="radio" name="q" value="wrong" id="q2b">b. Jaime Lannister
<br>
<input type="radio" name="q" value="wrong" id="q2c">c. Cersei Lannister
<br>
<input type="radio" name="q" value="wrong" id="q2d">d. Jon Snow
<br>
<button class="submit" type="submit">Submit</button>
</div>
<div class="q3">
<h3>Who is the King of the North?</h3>
<input type="radio" name="q" value="wrong" id="q3a">a. Bran Stark
<br>
<input type="radio" name="q" value="correct" id="q3b">b. Jon Snow
<br>
<input type="radio" name="q" value="wrong" id="q3c">c. Tommen Baratheon
<br>
<input type="radio" name="q" value="wrong" id="q3d">d. LittleFinger
<br>
<button class="submit" type="submit">Submit</button>
</div>
<div class="q4">
<h4>Who is the head of house Stark?</h4>
<input type="radio" name="q" value="wrong" id="q4a">a. Tyrion Lannister
<br>
<input type="radio" name="q" value="wrong" id="q4b">b. Jon Snow
<br>
<input type="radio" name="q" value="wrong" id="q4c">c. Bran Stark
<br>
<input type="radio" name="q" value="correct" id="q4d">d. Ned Stark
<br>
<button class="submit" type="submit">Submit</button>
</div>
<div class="q5">
<h5>Which persons are the 'Night's Watch' trying to stop by using a giant wall of ice?</h5>
<input type="radio" name="q" value="correct" id="q5a">a. White Walkers
<br>
<input type="radio" name="q" value="wrong" id="q5b">b. Wildings
<br>
<input type="radio" name="q" value="wrong" id="q5c">c. Mother of Dragons
<br>
<input type="radio" name="q" value="wrong" id="q5d">d. Night walkers
<br>
<button class="submit" type="submit">Submit</button>
</div>
</form>
这是我的Javascript
$(document).ready(function () {
console.log("ready!");
var question1 = $('.q1');
var question2 = $('.q2');
var question3 = $('.q3');
var question4 = $('.q4');
var question5 = $('.q5');
var correctAnswers = 0;
var wrongAnswers = 0;
var gameArr = [question1, question2, question3, question4, question5];
function nextGame() {
for (i=0;i<gameArr.length;i++){
//i dont want it to grab every object all at the same time
}
}
nextGame();
console.log(nextGame());
//My startGame button
$('.b1').on("click", function () {
console.log(gameArr[0]);
gameArr[0].show();
});
//Setting up audio for the start screen, make it loop so it never stops running
var audio1 = new Audio("assets/music/startMusic.mp3");
audio1.addEventListener('ended', function () {
this.currentTime = 0;
this.play();
}, false);
audio1.play();
//code to make my quiz responsive
function game() {
var answer = $("input[name='q']:checked").val();
if (answer === "correct") {
alert("Correct!");
correctAnswers = correctAnswers + 1
} else {
wrongAnswers = wrongAnswers + 1
alert("Wrong!");
}
}
//timer
function countdown() {
seconds = 60;
$('#timer').html('<h6>Time Remaining: ' + seconds + '</h6>');
time = setInterval(showCountdown, 1000);
}
function showCountdown() {
seconds--;
$('#timer').html('<h3>Time Remaining: ' + seconds + '</h3>');
if (seconds < 1) {
clearInterval(time);
}
}
//submit your answer
$('.submit').on("click", function () {
//nextGame();
game();
console.log(gameArr);
});
答案 0 :(得分:2)
你必须记住最后一个位置。
所以你有一个变量,称之为lastGame之类的东西。这将是与correctAnswers
等级相同的变量。从零开始。
每当您想要导航到下一个门时,请增加此值并执行gameArr[lastGame].show();
。
示例:
var correctAnswers = 0;
var wrongAnswers = 0;
var gameArr = [question1, question2, question3, question4, question5];
var lastGame = 0;
function nextGame() {
gameArr[lastGame].show();
lastGame++;
}
在超时时,您拨打nextGame()
答案 1 :(得分:0)
每当用户点击答案时,使全局迭代器增加其值,隐藏旧div显示新Div 像这样的东西
var question1 = $('.q1');
var question2 = $('.q2');
var question3 = $('.q3');
var question4 = $('.q4');
var question5 = $('.q5');
var correctAnswers = 0;
var wrongAnswers = 0;
var currentIndex = 0;
var gameArr = [question1, question2, question3, question4, question5];
然后提交表格后
$('.submit').on("click", function () {
//nextGame();
game();
if(currentIndex < (gameArr.length -1 ))
{
// I am using the hide callback which is fired by jQUery after the object is completely hidden
gameArr[currentIndex].hide(function(){
currentIndex++;
gameArr[currentIndex].show();
});
}
});
答案 2 :(得分:0)
首先,每个表单不应该有多个类型提交按钮。将提交按钮移动到表单结束标记之前。
每个问题都不需要变量。使用你的jquery(暂时没有使用jquery我现在都做出反应)你应该能够选择这样的问题
var questions = $('form div')
然后你需要一个当前的问题变量。也许所有的div都有一个隐藏的类。选择当前问题时,从当前div中删除该隐藏类。
当用户提交表单时,如果不增加当前问题并显示下一个问题的div,则可以检查它们是否在问题数组的末尾。你可以隐藏上一个问题或让它保持可见(由你决定)。