Question

我需要带有行结果的php结果

我的SQL表就像

ID | date      | material | Quantity
01 | 01/01/2018| abc      | 50
02 | 01/01/2018| abc      | 50
03 | 02/01/2018| def      | 50
04 | 03/01/2018| ghi      | 50

sql查询：

select sum(Quantity) as 'Total Quantity',* group by date

我需要结果为：

01/01/2018 | 02/01/2018 | 03/01/2018
100        |50          |50

这是我的计划：

while($row = mysqli_fetch_assoc($result))
{
    echo "<tr><td>".$row['Date']."</td></tr>";
    echo "<tr><td>".$row1['Total Quantity']."</td></tr>";
}

但我不知道如何在标题

中获取日期值

Answer 1

如果您使用标头值对结果集编制索引，则可以使用array_keys()轻松访问它们：

$sql    = "SELECT SUM(Quantity) as quantity, date GROUP BY date ORDER BY date";
$result = $conn->query($sql);

$rows = [];
while ($row = mysqli_fetch_assoc($result))
{
    $rows[$row['date']] = $row['quantity'];
}

$header = array_keys($rows);

echo "<table><tr>";
foreach ($header as $cell)
{
    echo "<th>$cell</th>";
}
echo "</tr><tr>";
foreach ($rows as $cell)
{
    echo "<td>$cell</td>";
}
echo "</tr></table>";

Answer 2

你可以这样做

$sql = "SELECT sum(Quantity) as Total_Quantity ,date from [Table] group by date order by date";
$result = $conn->query($sql);

while($row = mysql_fetch_assoc($result))
{
   echo $row['date']." ";
   echo $row['Total_Quantity']." ";
}

（未经测试，但这是它应该如何工作）

如何将sql表行作为标题

2 个答案: