Question

我正在尝试测试正确的表单与InlineModelAdmin

一起使用

我已将自定义表单设置为：

-- vim: set syntax=vhdl ts=8 sts=2 sw=2 et:

LIBRARY ieee;
USE ieee.std_logic_1164.ALL;
USE ieee.numeric_std.ALL;

ENTITY tb_controller IS
END tb_controller;

ARCHITECTURE behavior OF tb_controller IS

  COMPONENT controller IS PORT (
    btn                     : IN  std_logic_vector(3 DOWNTO 0);
    sw                      : IN  std_logic_vector(0 DOWNTO 0);
    o_mins, o_secs, o_wmins : OUT integer RANGE 0 TO 59;
    o_hours, o_whours       : OUT integer RANGE 0 TO 23;
    alarm                   : OUT std_logic;
    clk                     : IN  std_logic;
    reset                   : IN  std_logic );
  END COMPONENT;

  SIGNAL tb_clk:     STD_LOGIC := '0';
  SIGNAL tb_BTN:     STD_LOGIC_VECTOR(3 DOWNTO 0) := (OTHERS => '0');
  SIGNAL tb_SW:      STD_LOGIC_VECTOR(0 DOWNTO 0) := "0";
  SIGNAL tb_ring:    STD_LOGIC;
  SIGNAL tb_reset:   STD_LOGIC;
  SIGNAL tb_secs:    integer RANGE 0 to 59;
  SIGNAL tb_mins:    integer RANGE 0 to 59;
  SIGNAL tb_hours:   integer RANGE 0 to 23;
  SIGNAL tb_wmins:   integer RANGE 0 to 59;
  SIGNAL tb_whours:  integer RANGE 0 to 23;

BEGIN

  -- Generiere Wecker-Takt 2^13Hz = 8192Hz
  tb_clk <= NOT tb_clk after 61035 ns;

  -- Generiere Reset
  tb_reset <= '1', '0' after 250 us;

  -- Stellen der Uhrzeit:
  tb_BTN(0) <= '1' after 10 sec, '0' after 27 sec;  -- set time
  tb_BTN(1) <= '1' after 28 sec, '0' after 38 sec;  -- set alarm
  tb_BTN(2) <= '1' after 11 sec, '0' after 22250 ms, '1' after 29 sec, '0' after 32750 ms;  -- set Minutes
  tb_BTN(3) <= '1' after 23 sec, '0' after 26 sec, '1' after 34 sec, '0' after 37250 ms;  -- set Houres
  tb_SW(0)  <= '1' after 40 sec;  --activate alarm clock

TB : PROCESS 
BEGIN
  WAIT FOR 1 sec;
  IF (tb_ring = '1') THEN
    WAIT FOR 1 sec;
    ASSERT FALSE REPORT "Simulation completed." SEVERITY FAILURE;
  END IF;
END PROCESS;

  -- Instantiierung des Weckers IN der Testbench
  DeviceUnderTest:controller
    PORT MAP(
      clk       => tb_clk,
      btn       => tb_BTN,
      sw        => tb_SW,
      o_mins    => tb_mins,
      o_secs    => tb_secs,
      o_wmins   => tb_wmins,
      o_hours   => tb_hours,
      o_whours  => tb_whours,
      alarm     => tb_ring,
      reset     => tb_reset );

END ARCHITECTURE;

然而，当我尝试检查class RateInline(admin.TabularInline): model = Rate fk_name = 'project' extra = 1 form = RateForm确实正在使用时，我得到：

生成的模型形式：

RateForm

但我希望以前的形式是：

formsets = response.context['inline_admin_formsets']

ipdb> formsets[1].forms[0].__class__
<class 'django.forms.widgets.RateForm'>

此表单是仅在验证期间使用，还是在上下文数据中生成的RateForm小部件？

Answer 1

Django将您的form传递给modelform_factory以生成管理中使用的表单类（源代码）。这样就可以将模型管理选项（如fields）包含在形式。

我认为你不应该担心formsets[1].forms[0]的类型。将其视为实施细节。正如您在评论中所建议的那样，断言RateInline.form == RateForm就足够了，并且相信当您设置form时Django会做正确的事情。

如何从管理上下文数据中找到InlineModelAdmin？

1 个答案: