Question

我有记录：

 let a =  [{
            "resource" : "user",

            "permissions" : [ 
                "add", 
                "list", 
                "verify", 
                "add-credit", 
                "deactive", 
                "trash", 
                "edit", 
                "impersonate", 
                "active"
            ]
        }, 
        {
            "resource" : "company",

            "permissions" : [ 
                "list", 
                "verify", 
                "pending", 
                "reject"
            ]
        }];

我想将其转换为：

{"user":[ 
                "add", 
                "list", 
                "verify", 
                "add-credit", 
                "deactive", 
                "trash", 
                "edit", 
                "impersonate", 
                "active"
         ], 
        "company" : [ 
                "list", 
                "verify", 
                "pending", 
                "reject"
            ]
     };

这可以通过自定义函数来完成，并将结果存储到另一个变量。

我想要的是使用map，filter或es6中任何新的javascript功能。

我尝试过使用map。

 a.map(function (res){return res.resource})

Answer 1

使用reduce

var output = a.reduce( ( acc, c ) => {
  acc[ c.resource ] = c.permissions;
  return acc; //return accumulator
} ,{}) // initialize accumulator to {}

<强>解释

使用reduce 迭代并初始化累加器 acc 空对象 {}。

对于数组c中的每个项a

将c.resource值（用户和公司）作为属性分配给acc（累加器），该属性的值为{{1} }

c.permissions 累加器 return。

Answer 2

尽管使用reduce已经回答了这个问题，但这只是为了澄清它可以通过这种方式完成，如果你不理解reduce如何工作或者你不理解想要使用reduce

＆＃13;

let a =  [{
            "resource" : "user",

            "permissions" : [ 
                "add", 
                "list", 
                "verify", 
                "add-credit", 
                "deactive", 
                "trash", 
                "edit", 
                "impersonate", 
                "active"
            ]
        }, 
        {
            "resource" : "company",

            "permissions" : [ 
                "list", 
                "verify", 
                "pending", 
                "reject"
            ]
        }];
        
var res = {};
a.forEach((obj)=>{
  res[obj.resource] = obj.permissions;
});
console.log(res);

＆＃13;

es6：隐藏对象到数组

2 个答案: