Question

我尝试过阅读过很多帖子，但我仍然无法弄清楚如何处理此请求：

我有一张如下表格

+-------+---------------+------------+
| ID     |   Comp.    |    Role   |
+-------+---------------+------------+
| 1       |   abc         |     All     |
+-------+---------------+------------+
| 1       |   abc         |   Sales  |
+-------+---------------+------------+
| 2       |   def         |     All      |
+-------+---------------+------------+
| 3       |   zeh         |     All      |
+-------+---------------+------------+
| 3       |   zeh         |     TI      |
+-------+---------------+------------+

我想基于结果角色，如果一个特定ID有两个角色，一个是全部，另一个是销售那么我需要考虑销售行

输出应该是这样的

+-------+---------------+------------+
| ID     |   Comp.    |    Role   |
+-------+---------------+------------+
| 1       |   abc         |   Sales  |
+-------+---------------+------------+
| 2       |    def        |       All    |
+-------+---------------+------------+
| 3       |   zeh         |     TI      |
+-------+---------------+------------+

Answer 1

嗯。嗯。。。我认为这样做你想要的：

select t.*
from t
where t.role = 'Sales'
union all
select t.*
from t
where t.role <> 'Sales' and
      not exists (select 1 from t t2 where t2.id = t.id);

Answer 2

如果您只有2个角色值（'Sales'和'All'）

，这将有效

    create table #tmp(ID INT,Comp VARCHAR(10),Role VARCHAR(10))

    insert into #tmp
    SELECT 1,'abc','All'
    union ALL
    SELECT 1,'abc','Sales'
    union ALL
    SELECT 2,'def','All'


    select ID,Comp,MAX(Role) As Role from #tmp
    Group by Id,comp

    drop table #tmp

Answer 3

根据我的理解

dependencies {
    implementation fileTree(include: ['*.jar'], dir: 'libs')
    //noinspection GradleCompatible
    implementation 'com.android.support:appcompat-v7:27.0.2'
    implementation 'com.android.support.constraint:constraint-layout:1.0.2'
    implementation 'com.android.support:support-v4:27.0.2'
    testImplementation 'junit:junit:4.12'
    androidTestImplementation 'com.android.support.test:runner:1.0.1'
    androidTestImplementation 'com.android.support.test.espresso:espresso-core:3.0.1'
    //Recycleview
    implementation 'com.android.support:recyclerview-v7:27.0.2'
    //Butterknife
    implementation 'com.jakewharton:butterknife:8.8.1'
    annotationProcessor 'com.jakewharton:butterknife-compiler:8.8.1'
    //SDP
    implementation 'com.intuit.sdp:sdp-android:1.0.5'
    //OkHttp
    implementation 'com.squareup.okhttp3:logging-interceptor:3.9.1'
    //RxJava and RxAndroid
    implementation 'io.reactivex.rxjava2:rxjava:2.0.6'
    implementation 'io.reactivex.rxjava2:rxandroid:2.0.1'
    implementation 'io.ashdavies.rx:rx-firebase:1.3.3'
    //RxBinding
    implementation 'com.jakewharton.rxbinding:rxbinding-design:0.4.0'
    //Retrofit
    implementation 'com.squareup.retrofit2:retrofit:2.3.0'
    implementation 'com.squareup.retrofit2:adapter-rxjava:2.3.0'
    //Glide
    implementation 'com.github.bumptech.glide:glide:4.6.1'
    annotationProcessor 'com.github.bumptech.glide:compiler:4.6.1'
    //GSON
    implementation 'com.google.code.gson:gson:2.2.4'
    //Image Crop Library
    implementation 'com.theartofdev.edmodo:android-image-cropper:2.6.+'
    //Dagger Android
    implementation 'com.google.dagger:dagger:2.13'
    annotationProcessor 'com.google.dagger:dagger-compiler:2.13'
    annotationProcessor 'com.google.dagger:dagger-android-processor:2.13'
    implementation 'com.google.dagger:dagger-android-support:2.13'
    //Only applying android dagger.
    implementation 'com.android.support:cardview-v7:27.0.2'
    implementation 'com.android.support:multidex:1.0.2'
}

这可以正常查看此demo

Answer 4

如果您有其他功能，则应添加到CASE WHEN

SELECT
    ID
    , Comp
    , CASE WHEN role_id = 0 THEN 'All'
           WHEN role_id = 1 THEN 'Sales'
           WHEN role_id = 2 THEN 'TI' 
           ELSE NULL END AS Role
FROM
    (
    SELECT
        ID
        , Comp
        , MAX(CASE WHEN Role = 'All' THEN 0
                   WHEN Role = 'Sales' THEN 1
                   WHEN Role = 'TI' THEN 2 END 
                   ELSE -1 END) AS role_id
    FROM 
        t 
    GROUP BY
        ID
        , Comp
    )tmp

Answer 5

UNION ALL 将取代

select * from table 
where role <> 'All'
union all
select * from table t
where not exists (
    select 1 from table 
    where id = t.id and [comp.] = t.[comp.] and role <> 'All'
)
order by 1

结果：

ID  Comp.   Role
1   abc    Sales
2   def    All
3   zeh    IT

选择特定行但基于另一个列角色

5 个答案: