Question

我是redux-observable的新手，我创造了一部新的史诗。我的代码显示'（0，rxjs.ofType）不是函数。但是，我复制了那个

= (action$: Observable<Action>, store: any) => action$.pipe(
  ofType('SUCCESS_LOGIN'),

来自另一个不显示错误的文件。

有什么问题？

// @flow
import { combineEpics } from 'redux-observable';
import { Observable, ofType } from 'rxjs';
import { map, exhaustMap } from 'rxjs/operators';
import camelcaseKeysDeep from 'camelcase-keys-deep';
import * as actions from './actions';
import { request } from '../../lib/axios';

const getDeviceTokenEpic = (action$: Observable<Action>, store: any) => action$.pipe(
  ofType('SUCCESS_LOGIN'),
  exhaustMap(({ payload }) => request({
    url: `users/${store.getState().currentUser.user.id}`,
    method: 'put',
    data: {
      device_token: 'test',
      password: 'test',
    },
  }).pipe(
    map(data => camelcaseKeysDeep(data)),
    map(({ user, authToken }) => currentUserActions.successLogin({ user, authToken })),
    catchError((errorMessage: string) => Observable.of(actions.failLogin({ errorMessage }))),
  )),
);

export default combineEpics(
  getDeviceTokenEpic,
);

Answer 1

正如@cartant所说，ofType的功能来自redux-observable！

只需将其更改为：

import { ofType } from "redux-observable";

redux-observable cause（0，rxjs.ofType）不是函数

1 个答案: