Question

我想根据列表中包含的字符串打印出格式化的字符串。但是，我想打印出格式化的字符串以逗号停止。

示例：a = ['Apple pie, A couple of oranges, Eggs benedict, Chocolate Milkshake']

我希望我的格式化字符串看起来像这样：

Shopping list: 
Fruits: Apple pie, A couple of oranges
Poultry: Eggs benedict
Drinks: Chocolate Milkshake

我将如何完成这项工作？

Answer 1

您需要一本字典存储每种食物类型所属的名称和可能的食物项目：

testing = {'Fruits':['apple', 'oranges'], 'Poultry':['eggs'], 'Drinks':['Chocolate']}
a = ['Apple pie, A couple of oranges, Eggs benedict, Chocolate Milkshake']
a = a[0].split(', ')
final_data = "Shopping list:\n{}".format('\n'.join('{}: {}'.format(h, ', '.join(i for i in a if any(c.lower() in i.lower() for c in b))) for h, b in testing.items()))

输出：

Shopping list:
Fruits: Apple pie, A couple of oranges
Poultry: Eggs benedict
Drinks: Chocolate Milkshake

您可以通过添加其他食物类型（键）和相关术语（值列表）来扩展测试数据。

Answer 2

实际上，您没有存储足够的信息来创建您正在寻找的输出。我建议将您的信息存储在字典中，如下所示：

foods = {
    'Fruits': ['Apple pie', 'A couple of oranges'],
    'Poultry': ['Eggs benedict'],
    'Drinks': ['Chocolate Milkshake']
}

然后，您将获得创建所需输出所需的所有信息，如下所示：

output = 'Shopping list:\n'

for category in foods:

    category_str = ''
    for food in foods[category]:
        category_str += '{}, '.format(food)
    category_str = category_str[:-2] # cut off trailing comma and space

    output += '{}: {}\n'.format(category, category_str)

output = output[:-1] # cut off trailing newline

print(output)

Answer 3

SELECT c.id FROM c WHERE <filter>

从列表中打印格式化的字符串直到指定的字符

3 个答案: