Question

我想要显示的SQL结果，每个人都有不同的活动，每个活动的价格加上费用。我和他们一起分组（见附图）。突出显示的结果为黄色，应该是我的最终报告。请帮忙。赋予的

SQL查询：

SELECT DISTINCT Name, Surname, TypeParticipant, i.IDBill, ip.Idparticipant, cast((f.couttotal / 100.0) AS DECIMAL(20, 2)) AS price, left(f.texte, 20) AS ActivityName, a.Activityfee, convert(VARCHAR, g.datedebut, 111) DateDébut, convert(VARCHAR, g.datefin, 111) DateFIn
FROM Fin.FactureItem i
LEFT JOIN ins.Inscription ip
    ON ip.Idinscription = i.IDinscription
LEFT JOIN Fin.FactureItem f
    ON f.IDfacture = i.IDfacture
INNER JOIN Part.participant p
    ON p.idparticipant = ip.idparticipant
INNER JOIN Acts.Groupe g
    ON g.idgroupe = ip.idgroupe
INNER JOIN Acts.Activite a
    ON a.idactivite = g.idactivite
INNER JOIN Part.ParticipantTypeParticipant t
    ON p.idparticipant = t.idparticipant – Blessed 11 secs ago
INNER JOIN Part.TypeParticipant ct
    ON ct.idtypeparticipant = t.idtypeparticipant
WHERE i.IDfacture IS NOT NULL
    AND i.idinscription IS NOT NULL
    AND p.idparticipant IN (
        45103
        ,12354
        )

results

Answer 1

所有其他列都需要aggregation。这将根据您在image中的输出而生效。但是，我认为最高价应该是230美元。无论如何，根据我们的输出，我需要修改查询。您可能需要进一步的子查询。

     WITH cte
AS (
    SELECT DISTINCT nom
        ,prenom
        ,TitreFRA AS TypeParticipant
        ,i.IDfacture AS IDBill
        ,ip.Idparticipant
        ,cast((f.couttotal / 100.0) AS DECIMAL(20, 2)) AS price
        ,left(f.texte, 20) AS Activityandfees
        ,a.nomFra Activityname
        ,convert(VARCHAR, g.datedebut, 111) DateDébut
        ,convert(VARCHAR, g.datefin, 111) DateFIn
    FROM Finances.FactureItem i
    LEFT JOIN Inscriptions.Inscription ip ON ip.Idinscription = i.IDinscription
    LEFT JOIN Finances.FactureItem f ON f.IDfacture = i.IDfacture
    INNER JOIN participants.participant p ON p.idparticipant = ip.idparticipant
    INNER JOIN Activites.Groupe g ON g.idgroupe = ip.idgroupe
    INNER JOIN Activites.Activite a ON a.idactivite = g.idactivite
    INNER JOIN Participants.ParticipantTypeParticipant t ON p.idparticipant = t.idparticipant
    INNER JOIN participants.TypeParticipant ct ON ct.idtypeparticipant = t.idtypeparticipant
    WHERE i.IDfacture IS NOT NULL AND i.idinscription IS NOT NULL AND p.idparticipant IN (
            4513
            ,12354
            )
    )
    ,CT1
AS (
    SELECT nom
        ,prenom
        ,TypeParticipant
        ,Activityname
        ,DateDébut
        ,Activityandfees
        ,price
        ,ROW_NUMBER() OVER (
            PARTITION BY ACTIVITYANDFEES
             ORDER BY ACTIVITYNAME DESC
            ) rn
    FROM cte
    )
    ,ct2
AS (
    SELECT NOM
        ,PRENOM
        ,TYPEPARTICIPANT
        ,ACTIVITINAME
        ,Price
        ,0 Price1
        ,0 price2
        ,0 price3
      FROM ct1
      WHERE Activityandfees = 'Ajout de I Activite' AND rn = 1
    UNION ALL

    SELECT NOM
        ,PRENOM
        ,TYPEPARTICIPANT
        ,ACTIVITINAME
        ,0 Price
        ,price price1
        ,0 price2
        ,0 price3

    FROM ct1
    WHERE Activityandfees = 'Frias daccompagname' AND rn = 1

    UNION ALL

    SELECT NOM
        ,PRENOM
        ,TYPEPARTICIPANT
        ,ACTIVITINAME
        ,0 Price
        ,0 price1
        ,price price2
        ,0 price3

    FROM ct1
      WHERE Activityandfees = 'Frias dinscription' AND rn = 1

    UNION ALL

    SELECT NOM
        ,PRENOM
        ,TYPEPARTICIPANT
        ,ACTIVITINAME
        ,0 Price
        ,0 price1
        ,0 price2
        ,price Price3

    FROM ct1
    WHERE Activityandfees = 'Subvention' AND rn = 1
    )
SELECT NOM
    ,PRENOM
    ,TYPEPARTICIPANT
    ,ACTIVITINAME
    ,sum(cast(price as float)) AjoutActivityprice
    ,sum(cast(price1 as float)) daccompagnameActivityprice
    ,sum(cast(price2 as float)) dinscriptionActivityprice
    ,sum(cast(price3 as float)) Subventionprice
FROM ct2
GROUP BY NOM
    ,PRENOM
    ,TYPEPARTICIPANT
    ,ACTIVITINAME

SSRS设计报告

1 个答案: