访问flask socketio后台任务中的应用程序上下文

时间:2018-03-05 14:52:40

标签: python flask flask-socketio

我正在使用 Flask-SocketIO 库开发 Flask 应用程序,以实现服务器后台任务与客户端之间的实时通信。

我需要在后台任务中访问我的数据库,我不知道如何实现它,因为没有初始化应用程序上下文。

我的代码是:

@socketio.on('connect', namespace='/rt/notifications/')
def start_notifications_thread():
    global thread
    with thread_lock:
        if thread is None:
            thread = socketio.start_background_task(target=notifications_job)

def notifications_job():
    last_alert_id = None
    while True:
        socketio.sleep(60)
        last_id = Alert.get_last_alert_id()  # Flask-SQLAlchemy model
        if last_alert_id is not None and last_id != last_alert_id:
            socketio.emit('new_alerts', {'msg': 'New alert', 'id': last_id}, namespace='/rt/notifications/')
        last_alert_id = last_id

1 个答案:

答案 0 :(得分:1)

根据flask-socketio的作者 miguelgrinberg ,以下是正确的方法。简单地说,我必须将我的应用实例传递给notifications_job方法,如下所示:

from threading import Lock

from flask import current_app

from .. import socketio

thread = None
thread_lock = Lock()

def notifications_job(app):
    last_alert_id = None
    with app.app_context():
        while True:
            socketio.sleep(60)
            last_id = Alert.get_last_alert_id()  # Flask-SQLAlchemy   model
            if last_alert_id is not None and last_id != last_alert_id:
                socketio.emit('new_alerts', {'msg': 'New alert', 'id': last_id}, namespace='/rt/notifications/')
            last_alert_id = last_id

@socketio.on('connect', namespace='/rt/notifications/')
def start_notifications_thread():
    global thread
    with thread_lock:
        if thread is None:
            thread = socketio.start_background_task(notifications_job, current_app._get_current_object())