在Hive中将行转换为列

Question

我在hive中有一个表格，其结构如下：

+------+------+--------+-------+
| col1 | col2 |  col3  | Value |
+------+------+--------+-------+
|    1 | A1   | M1     |    23 |
|    1 | A1   | M1_LW  |    25 |
|    1 | A1   | M1_L2W |    22 |
|    1 | A1   | M2     |    17 |
|    1 | A1   | M2_LW  |    21 |
|    1 | A1   | M2_L2W |    13 |
|    1 | A1   | M3     |    16 |
|    1 | A1   | M3_LW  |    30 |
|    1 | A1   | M3_L2W |    11 |
|    2 | A2   | M1     |    22 |
|    2 | A2   | M1_LW  |    22 |
|    2 | A2   | M1_L2W |    10 |
|    2 | A2   | M2     |    14 |
|    2 | A2   | M2_LW  |    25 |
|    2 | A2   | M2_L2W |    23 |
|    2 | A2   | M3     |    10 |
|    2 | A2   | M3_LW  |    20 |
|    2 | A2   | M3_L2W |    25 |
+------+------+--------+-------+

从查询的角度来看，这种结构足以满足需求，但是对于特定的报告需求，需要将表转换为如下所示：

+------+------+-------+----+----+----+
| col1 | col2 | col3  | M1 | M2 | M3 |
+------+------+-------+----+----+----+
|    1 | A1   | Today | 23 | 17 | 16 |
|    1 | A1   | LW    | 25 | 21 | 30 |
|    1 | A1   | L2W   | 22 | 13 | 11 |
|    2 | A2   | Today | 22 | 14 | 10 |
|    2 | A2   | LW    | 22 | 25 | 20 |
|    2 | A2   | L2W   | 10 | 23 | 25 |
+------+------+-------+----+----+----+

您可以使用hive中提供的内置功能来帮助您。我已尝试使用pivot和union的结果，但它会成为一个性能开销。 尝试使用to_map UDAF，但正在使用的hive版本似乎不支持它。 任何意见都将不胜感激。

Answer 1

您可以使用select col1, col2, (case when col3 like '%_LW' then 'LW' when col3 like '%_L2W' then 'L2W' else 'Today' end) as col3, max(case when col3 like 'M1%' then value end) as m1, max(case when col3 like 'M2%' then value end) as m2, max(case when col3 like 'M3%' then value end) as m3 from t group by col1, col2, (case when col3 like '%_LW' then 'LW' when col3 like '%_L2W' then 'L2W' else 'Today' end) 和条件聚合：

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